The velocity of a particle moving in the x-y plane is given by (6.07i+ 4.97j) m/s at time t = 3.87 s. Its average acceleration during the next 0.014 s is (7.5i + 5.0j) m/s². Determine the velocity v of the particle at t = 3.884 s and the angle between the average- acceleration vector and the velocity vector at t = 3.884 s. Answers: v (6.18 0= P 0 i+ i 4.97 j) m/s

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter2: Motion In One Dimension
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Your answer is partially correct.
The velocity of a particle moving in the x-y plane is given by (6.07i+ 4.97j) m/s at time t = 3.87 s. Its average acceleration during the
next 0.014 s is (7.5i + 5.0j) m/s². Determine the velocity v of the particle at t = 3.884 s and the angle between the average-
acceleration vector and the velocity vector at t = 3.884 s.
Answers:
v = ( 6.18
0 = i
0
i+ i
4.97
j) m/s
Transcribed Image Text:- Your answer is partially correct. The velocity of a particle moving in the x-y plane is given by (6.07i+ 4.97j) m/s at time t = 3.87 s. Its average acceleration during the next 0.014 s is (7.5i + 5.0j) m/s². Determine the velocity v of the particle at t = 3.884 s and the angle between the average- acceleration vector and the velocity vector at t = 3.884 s. Answers: v = ( 6.18 0 = i 0 i+ i 4.97 j) m/s
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