Question
Asked Oct 4, 2019
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PLEASE HELP!

The velocity vs. time graph for an object moving along a straight path is shown in the figure below.
(m/s)
6
4
2
t(s)
20
15
10
-2
-4
-8
(i) Find the average acceleration of this object during the following time intervals.
0 s to 5.0 s
(a)
m/s2
5.0 s to 15 s
(b)
m/s2
(c)
0 s to 20 s
m/s2
(ii) Find the instantaneous accelerations at the following times.
2.0 s
(a)
m/s2
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The velocity vs. time graph for an object moving along a straight path is shown in the figure below. (m/s) 6 4 2 t(s) 20 15 10 -2 -4 -8 (i) Find the average acceleration of this object during the following time intervals. 0 s to 5.0 s (a) m/s2 5.0 s to 15 s (b) m/s2 (c) 0 s to 20 s m/s2 (ii) Find the instantaneous accelerations at the following times. 2.0 s (a) m/s2

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10 s
(b)
m/s2
18 s
(c)
m/s2
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10 s (b) m/s2 18 s (c) m/s2

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Expert Answer

Step 1

Given:

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v (m/s) 8 4 2 t (s Ло 5 15 -2 -6 20

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Step 2

(i) Calculating the average acceleration of the object for part (a):

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Average acceleration = Total change in velocity Total time taken Initial velocity at t 0s, u = - 8 m/s Final velocity at t = 5s, v = - 8 m/s Totak change in velocity = 0 m/s - Total time taken = 5 s Total change in velocity Om/s Average acceleration, a, 0 Total time taken 5.s amg =0

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Step 3

Calculating the average acceler...

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Initial velocity at t 5s, u = -8 m/s Final velocity at t = 15s, v = + 8 m/s Totak change in velocity 8 m/s (8 m/s) 16 m/s Total time taken = 15 s - 5 s = 10 s Total change in velocity_ 16m/s _16 m/s Average acceleration, ar ang Total time taken 10s aay 1.6 m/s2 Initial velocity at t = 15 s, u = 8 m/s Final velocity at t = 20 s, v = 8 m/s Totak change in velocity 0 m/s Total time taken = 5 s Total change in velocity Om/s Average acceleration, 0 ang Total time taken 5.s an's

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Tagged in
SciencePhysics

Kinematics

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