There are six telephone lines in a company. Let X denote the number of lines in use at aspecified time. The probability mass function of X is as given as follow:01234.10.15Xp(x)a. 0.21Ob. None of the answers.20What is the probability of less than three lines are in use?c. 0.47d. 0.45.25.205.066.04

Answered: Image /qna-images/answer/8ca6f541-861a-46bb-bf5e-d2899b34f7e5.jpg

Answered: There are six telephone lines in a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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a. What value of c will make f(x) a valid probability mass function ?b. Compute P (1 < X < 6).
The number of trams X arriving at the St. Peter's Square tram stop every t minutes has the following probability mass function: p(x) =(0.25t)^x/x! * exp(-0.25t) for x=0,1,2,... the probability that 3 to 5 trams arrive in a 6 minute period is
A survey of cars on a certain stretch of highway during morning commute hours showed that 70% had only one occupant, 15% had 2, 10% had 3, 3% had 4, and 2% had 5. Let X represent the number of occupants in a randomly chosen car. a) Find the probability mass function of X. b) Find P(X ≤ 2). c) Find P(X > 3). d) Find μX. e) Find σX.
The General Social Survey asked a sample of adults how many siblings (brothers and sisters) they had (X) and also how many children they had (Y). We show results for those who had no more than 4 children and no more than 4 siblings. Assume that the joint probability mass function is given in the following contingency table: y x 0 1 2 3 4 0 0.03 0.01 0.02 0.01 0.01 1 0.09 0.05 0.08 0.03 0.01 2 0.09 0.05 0.07 0.03 0.02 3 0.06 0.04 0.07 0.04 0.02 4 0.04 0.04 0.04 0.03 0.02 Find the conditional expectation E(Y|X = 4). (Round the final answer to four decimal places.)
The General Social Survey asked a sample of adults how many siblings (brothers and sisters) they had (X) and also how many children they had (Y). We show results for those who had no more than 4 children and no more than 4 siblings. Assume that the joint probability mass function is given in the following contingency table: y x 0 1 2 3 4 0 0.03 0.01 0.02 0.01 0.01 1 0.09 0.05 0.08 0.03 0.01 2 0.09 0.05 0.07 0.03 0.02 3 0.06 0.04 0.07 0.04 0.02 4 0.04 0.04 0.04 0.03 0.02 Find the conditional probability mass function pY|X(y|4). (Round the final answer to four decimal places.) pY|X(0|4) = pY|X(1|4) = pY|X(2|4) = pY|X(3|4) = pY|X(4|4) = Find the conditional probability mass function pX|Y (x|3). (Round the final answer to four decimal places.) pX|Y(0|3) = pX|Y(1|3) = pX|Y(2|3) = pX|Y(3|3) = pX|Y(4|3) = Find the conditional expectation E(X|Y = 3). (Round the final answer to four decimal places.) E(X|Y = 3) =
The General Social Survey asked a sample of adults how many siblings (brothers and sisters) they had (X) and also how many children they had (Y). We show results for those who had no more than 4 children and no more than 4 siblings. Assume that the joint probability mass function is given in the following contingency table: y x 0 1 2 3 4 0 0.03 0.01 0.02 0.01 0.01 1 0.09 0.05 0.08 0.03 0.01 2 0.09 0.05 0.07 0.04 0.02 3 0.06 0.04 0.07 0.04 0.02 4 0.04 0.03 0.04 0.03 0.02 Find ρ(X, Y). (Round the final answer to four decimal places.) ρ(X, Y) =
Given a discrete RV X that takes on the values {-2, -1, 3, 4} and whose pmf (probability mass function) is: p-2 = 0.1 , p-1 = 0.2 , p3 = 0.6 , p 4 = 0.1 . Calculate the mean μ X of RV X.
Let Y1 = 0.5, Y2 = 0.25, Y3 = 0.75, Y4 = 0.25 and Y5 = 1.25 be a random sample of width 5 selected from the population with the following probability density function. Which of the following is the estimation value obtained by the moment method for the unknown q parameter of this population?
I toss a fair coin twice, and let X be defined as the number of heads I observe. Find the range of X, RX, as well as its probability mass function PX.
Suppose that that joint probability mass function of X and Y is given in the following table. p(x,y) y 0 1 0 0.09 0.03 x 1 ? 0.17 2 0.13 0.09 Find the expected value of X.(Hint: First, find p(1,0). Then, you might want to find the (marginal) pdf of X).(Answer as a decimal number, and round to 2 decimal places).
The probability mass function of X = the number of major defects in an electrical appliance of a randomly selected type is: Calculate the following:a) E (X)b) V (X) directly from the definition
I toss a coin 4 times, and let X be defined as the number of heads I observe. Find the range of X, RX, as well as its probability mass function PX.

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