There are two important parts to every simple recursive function: the base case, and the recursive call that makes progress towards the base case. Something that can go wrong with recursion when it is used incorrectly is a stack overflow. Explain two different ways that a recursive function could be written incorrectly that could lead to stack overflow. Hint: one has something to do with the base case, and the other with the recursive call. 1. Enter your answer here 2. Enter your answer here

There are two important parts to every simple recursive function: the base case, and the recursive call that makes progress towards the base case. Something that can go wrong with recursion when it is used incorrectly is a stack overflow. Explain two different ways that a recursive function could be written incorrectly that could lead to stack overflow. Hint: one has something to do with the base case, and the other with the recursive call. 1. Enter your answer here 2. Enter your answer here

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Consider the following recursive function to compute factorialint fact (int n) {if (n <= 1)return 1;elsereturn n * fact(n-1);}int main() {cout << fact(5) << endl;return 0;} Show the stack of activation records each time the function fact is called (either directly or recursively). Each activation record needs to be identified by the name of the function and the parameter value, but there is no need to elaborate the specific content of each activation record.
Write a recursive Racket function "update-if" that takes two functions, f and g, and a list xs as parameters and evaluates to a list. f will be a function that takes one parameter and evaluates true or false. g will be a function that takes one parameter and evaluates to some output. The result of update-if should be a list of items such that if x is in xs and (f x) is true, then (g x) is in the list. The output list's elements should keep the input list's items in the same relative order. For example (update-if even? add1 '(1 2 3 4)) should evaluate to '(3 5) because 2 and 4 make even? true and add1 turns 2 and 4 into 3 and 5.
The goal is to rewrite the function, below, such that passes in a different list of parameters, particularly eliminating the need to pass low and high for each recursive call to binary_search. defbinary_search(nums,low,high,item): mid=(low+high)//2iflow>high:returnFalse #The item doesn't exist in the list!elifnums[mid]==item:returnTrue# The item exists in the list!elifitem<nums[mid]:returnbinary_search(nums,low,mid-1,item)else:returnbinary_search(nums,mid+1,high,item) The new function should be prototyped below. The number of changes between the given version, and the one requested is not significant. defbinary_search(nums,item):pass# Remove this and fill in with your code Tip: If you consider that high and low are used to create a smaller version of our problem to be processed recursively, the version requested will do the same thing, just through a different, more Pythonic technique.
Lee has discovered what he thinks is a clever recursive strategy for printing the elements in a sequence (string, tuple, or list). He reasons that he can get at the first element in a sequence using the 0 index, and he can obtain a sequence of the rest of the elements by slicing from index 1. This strategy is realized in a function that expects just the sequence as an argument. If the sequence is not empty, the first element in the sequence is printed and then a recursive call is executed. On each recursive call, the sequence argument is sliced using the range 1:. Here is Lee’s function definition: def printAll(seq): if seq: print(seq[0]) printAll(seq[1:]) Write a program that tests this function and add code to trace the argument on each call. Does this function work as expected? If so, are there any hidden costs in running it?
part 1. draw the recursive call tree for the following function when its called with a(7) int a (int n) { if (n % 4== 0) { return n+1;} else { return a(n-1) + a (n*4); } } part 2. what is the returning value?
In Kotlin, Write a recursive function with an expression body that takes an Int n and returns a list of the areas of circles for each radius from n to 1 (in decreasing order.) Get the areas by calling the area function. Then rewrite the recursive function so that the areas appear in increasing order. You do not need to use tail recursion in this case
Write a recursive function that, given a sequence of comparable values, returns the count of elements where the current element is less than the following ( next ) element in the given sequence. See the examples given below. def count_ordered ( seq ) : """ Input : A sequence of comparable elements Output : The number of elements that are less than the following element in the sequence Example : >>> count_ordered ( [ 1 , 2 , 3 , 4 , 5 , 6 ] ) 5 >>> count_ordered ( ( 1 , 12, 7.3 , -2,4 ) ) 2 >>> count_ordered ( 'Python' ) 2 >>> count_ordered ( [ 6 ] ) 0 >>> count_ordered ( [ ] ) 0 """ In the first example above , count_ordered ( [ 1,2,3,4,5,6 ] )the returned answer is 5 because for all the first 5 numbers the current number is less than the next number. In the second example above, count_ordered ( ( 1,12,7.3 , -2,4 ) )the…
Recursion can be direct or indirect. It is direct when a function calls itself and it is indirect recursion when a function calls another function that then calls the first function. To illustrate solving a problem using recursion, consider the Fibonacci series: - 1,1,2,3,5,8,13,21,34...The way to solve this problem is to examine the series carefully. The first two numbers are 1. Each subsequent number is the sum of the previous two numbers. Thus, the seventh number is the sum of the sixth and fifth numbers. More generally, the nth number is the sum of n - 2 and n - 1, as long as n > 2.Recursive functions need a stop condition. Something must happen to cause the program to stop recursing, or it will never end. In the Fibonacci series, n < 3 is a stop condition. The algorithm to use is this: 1. Ask the user for a position in the series.2. Call the fib () function with that position, passing in the value the user entered.3. The fib () function examines the argument (n). If n < 3…
Write and test a recursive function max to find the largest number in a list.The max is the larger of the first item and the max of all the other items.
For function decToBinary, write the missing parts of the recursion case. This function should return a string that stores the binary equivalent for int variable num. Example: The binary equivalent of 13 may be found by repeatedly dividing 13 by 2. So, 13 in base 2 is represented by the string "1101". Examples: decToBinary(13) -> "1101" public String decToBinary (int num) { if (num < 2) return Integer.toString(num); else return <<Missing recursive call>> + <<Missing calculation>>;}
python code Write a recursive function such that, given a list of intergers (say v) and an integer value (say x), the function returns resulting subset if there is a subset of intergers in v that sum up to x. Otherwise the function returns an empty list; Also write a sample code that runs this function using an example list and value x, and state the expected result
The Binary Search algorithm works by testing a mid-point, then eliminating half of the list. In this exercise, you are going to take our binary search algorithm and add print statements so that you can track how the search executes. Inside of the recursive binary search function, add print statements to print out the starting, ending, and midpoint values each time. Then as you test a value, print out the results, either too high, too low, or a match. Sample Output Starting value: 0 Ending value: 9 Testing midpoint value: 4 Too high! Starting value: 0 Ending value: 3 Testing midpoint value: 1 Too low! Starting value: 2 Ending value: 3 Testing midpoint value: 2 Match!