In dogs, the brown fur allele (B) is dominant to the white fur allele (b), and on a different chromosome, the curly fur allele (Q) is dominant to the straight fur allele (q). Quilty has brown and curly fur (BbQq) and she mates with Razor, who has brown and straight fur (Bbqq). Part 1 Fill in the missing parts of the Punnett square for this cross. Razor's gametes are shown on the left, and Quilty's are shown along the top. Bq BQ BBqq Bbqq Brown, curly + bQ Bbqq BbQq BBQq Bq bq bbQq bbqq Part 2 Fill in the phenotypic ratios of the F1 generation from the cross between Quilty (BbQq) and Razor (Bbqq). White, curly: ♦ Brown, straig ✓ - 2 3 4 1 White, straight:

In dogs, the brown fur allele (B) is dominant to the white fur allele (b), and on a different chromosome, the curly fur allele (Q) is dominant to the straight fur allele (q). Quilty has brown and curly fur (BbQq) and she mates with Razor, who has brown and straight fur (Bbqq). Part 1 Fill in the missing parts of the Punnett square for this cross. Razor's gametes are shown on the left, and Quilty's are shown along the top. Bq BQ BBqq Bbqq Brown, curly + bQ Bbqq BbQq BBQq Bq bq bbQq bbqq Part 2 Fill in the phenotypic ratios of the F1 generation from the cross between Quilty (BbQq) and Razor (Bbqq). White, curly: ♦ Brown, straig ✓ - 2 3 4 1 White, straight:

Name: In dogs, the brown fur allele (B) is dominant to the white fur allele
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Description: In dogs, the brown fur allele (B) is dominant to the white fur allele (b), and on a differentchromosome, the curly fur allele (Q) is dominant to the straight fur allele (q). Quilty hasbrown and curly fur (BbQq) and she mates with Razor, who has brow

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter15: Genomes And Genomics

Section: Chapter Questions

Problem 2QP: Hemophilia and color blindness are both recessive conditions caused by genes on the X chromosome. To...

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In dogs, black coat color (B) is dominant to yellow coat color (b), and straight fur (C) is dominant to curly fur (c). The coat color gene and the fur texture gene are on different chromosomes, so they assort independently, and are not sex-linked. In a cross between two BbCc parents, given that an offspring has black coat color and straight fur, what's the probability that it is heterozygous for both genes? Give 2 digits past the decimals.
In mice, the trait for high cholesterol is specified by a dominant allele designated HC, whereas the wild-type allele for normal cholesterol levels is designated hc. Black fur is specified by a recessive allele designated bl, whereas the wild-type allele which gives brown fur is designated BL. The genes for both of these traits are 30cM apart on the same autosome. A brown female (#1) with high cholesterol is mated to a black male (#2) with normal cholesterol. The progeny from this cross include a brown male (#3) with high cholesterol and a black female (#4) with normal cholesterol. What is the probability that the black mouse in the progeny of the first cross will also have high cholesterol?
In cats, black fur (B) is dominant over brown fur (b). Also, striped fur (A) is dominant over solid colored fur (a). What is the phenotype of a cat with the genotype Bbaa? What combinations of gametes could the Bbaa cat make? If the Bbaa cat mated with a cat that was heterozygous for both the color and pattern genes, what fraction of their kittens would be likely to have solid brown fur? Hint: draw your square on a separate paper to figure it out.
In humans, brown eyes (B) are dominant over blue. A brown eyed man marries a blue-eyed (b) woman and they have three children two of whom are brown-eyed and one of whom is blue-eyed. if the male has brown eyes but has a blue-eyed child, what must his genotype be?
In a breed of cattle, rough coat is dominant over smooth coat and black coat is codominant to red. Is the loci of the two pairs of gene concerned on the same chromosome?
In rats, kinky hairs and long nose whiskers are produced in response to therecessive gene (k), and a short stubby tail is produced by the recessive gene (st).The 2 loci of are 30 CM apart. What is the probability that in a cross between aheterozygous trans female rat and a heterozygous cis male rat, a combination of 2wild: 1 wild, short tail: 1 wild, kinky hair: 1 kinky hair, short tail pups will be found ina litter of 5.
In humans, the genetic disease cystic fibrosis is caused by a recessive allele (a). The normal (healthy) allele is dominant (A). What is the genotype of someone who has cystic fibrosis? What are the two different genotypes that a healthy person could have? If two people were both heterozygous for the cystic fibrosis gene, what fraction of their children would be likely to have this disease? Hint: Draw a Punnett square to figure it out.
In guinea pigs, the allele for short hair is dominant.What genotype would a heterozygous short-haired guinea pig have? _____What genotype would a pure-breeding short-haired guinea pig have? _____What genotype would a long-haired guinea pig have? _____
. In fruit flies (Drosophila melanogaster), the bn+ allele for normal dull red eyes is dominant to the bn allele that gives brown eyes. Another gene affects wing shape; for this gene, the ct+ allele for normal wings is dominant to the ct allele, which gives “cut” wings, with jagged edges. A fly with dull red eyes and normal wings was crossed with a fly that had dull red eyes and cut wings, and the following progeny were obtained: 16 dull red eyes, normal wings 14 dull red eyes, cut wings 5 brown eyes, normal wings 5 brown eyes, cut wings What were the genotypes of the parents?
In humans, the genes for colorblindness and hemophilia are both located on the X chromosome with no corresponding gene in the Y. These are both recessive alleles. If a man and a woman, both with normal vision, marry and have a colorblind son, draw the Punnet square that illustrates this. If the man dies and the woman remarries a colorblind man, draw a Punnet Square showing the type of children that could be expected from the second marriage. How many/what percentages of each could be expected.
In humans, free ear lobes (E) is dominant over attached ear lobes (e), and brown eyes (B) is dominant over blue eyes (b). A man with free ear lobes and brown eyes married a woman with attached ear lobes and brown eyes. Of four children, one has free ear lobes and brown eyes, one has free ear lobes and blue eyes, one has attached ear lobes and brown eyes, and one has attached ear lobes and blue eyes. Determine the genotypes of both parents.
Hemophilia and color blindness are both recessive conditions caused by genes on the X chromosome. To calculate the recombination frequency between the two genes, you draw a large number of pedigrees that include grandfathers with both hemophilia and color blindness, their daughters (who presumably have one chromosome with two normal alleles and one chromosome with two mutant alleles), and the daughters sons. Analyzing all the pedigrees together shows that 25 grandsons have both color blindness and hemophilia, 24 have neither of the traits, 1 has color blindness only, and 1 has hemophilia only. How many centimorgans (map units) separate the hemophilia locus from the locus for color blindness?