This assignment is worth 1 points. The extra point will be added to your overall course grade. For example: if you receive an 88% in the course you can receive up to 1 point giving you a new score of 89%. The following rubric will be used. 0.25 point for using the correct formula to solve the problem0.25 point for substituting the correct values into the formula. 0.5 point for obtaining the correct answer.  All work must be shown in order to receive any credit. Please upload your completed assignment here.  Helen plays basketball. For free throws, she makes the shot 78% of the time. Helen must now attempt two free throws. C = the event that Helen makes the first shot. P(C) = 0.78. D = the event Helen makes the second shot. P(D) = 0.78. The probability that Helen makes the second free throw given that she made the first is 0.86. What is the probability that Helen makes both free throws?

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Asked Jan 4, 2020
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This assignment is worth 1 points. The extra point will be added to your overall course grade. For example: if you receive an 88% in the course you can receive up to 1 point giving you a new score of 89%. The following rubric will be used. 

0.25 point for using the correct formula to solve the problem

0.25 point for substituting the correct values into the formula. 

0.5 point for obtaining the correct answer. 

 

All work must be shown in order to receive any credit. 

Please upload your completed assignment here. 

 

Helen plays basketball. For free throws, she makes the shot 78% of the time. Helen must now attempt two free throws. C = the event that Helen makes the first shot. P(C) = 0.78. D = the event Helen makes the second shot. P(D) = 0.78. The probability that Helen makes the second free throw given that she made the first is 0.86. What is the probability that Helen makes both free throws?

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Expert Answer

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Step 1

Given that,

Consider C and D be the events Helen makes the first and the second shot respectively.

P (C) = 0.78

P (D) = 0.78 and

 P (D|C) = 0.86.

Step 2

The probability that Helen makes both free throws can be obtained as:

P (C AND D) =P (D|C) P (C)

                            = (0.86) (0.78)

                            = 0.6708

Therefore, the required probability is 0.6708.

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