Three components are connected to form a system as shown in the accompanying diagram. Because the components in the 2-3 subsystem are connected in parallel, that subsystem will function if at least one of the two individual components functions. For the entire system function, component 1 must function and so must the 2-3 subsystem. The experiment consists of determining the condition of each component [S (success) for a functioning component and F (failure) for a nonfunctioning component]. (Enter your answers in set notation. Enter EMPTY or o for the empty set.) (a) Which outcomes are contained in the event A that exactly two of the three components function? A - (b) Which outcomes are contained in the event 8 that at least two of the components function? 8- (c) Which outcomes are contained in the event C that the system functions?
Three components are connected to form a system as shown in the accompanying diagram. Because the components in the 2-3 subsystem are connected in parallel, that subsystem will function if at least one of the two individual components functions. For the entire system function, component 1 must function and so must the 2-3 subsystem. The experiment consists of determining the condition of each component [S (success) for a functioning component and F (failure) for a nonfunctioning component]. (Enter your answers in set notation. Enter EMPTY or o for the empty set.) (a) Which outcomes are contained in the event A that exactly two of the three components function? A - (b) Which outcomes are contained in the event 8 that at least two of the components function? 8- (c) Which outcomes are contained in the event C that the system functions?
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter2: Systems Of Linear Equations
Section2.4: Applications
Problem 16EQ
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![Three components are connected to form a system as shown in the accompanying diagram. Because the components in the 2-3 subsystem are connected in parallel, that subsystem will function if at least one of the two individual components functions. For the entire system to
function, component 1 must function and so must the 2-3 subsystem.
2
[마
The experiment consists of determining the condition of each component [S (success) for a functioning component and F (failure) for a nonfunctioning component]. (Enter your answers in set notation. Enter EMPTY or ø for the empty set.)
(a) Which outcomes are contained in the event A that exactly two of the three components function?
A
%3D
(b) Which outcomes are contained in the event B that at least two of the components function?
B =
(c) Which outcomes are contained in the event C that the system functions?
C =
(d) List outcomes in C'.
C' =
List outcomes in A UC.
AUC-
List outcomes in AN C.
ANC=
List outcomes in BU C.
BUC =
List outcomes in B n C.
BnC =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F13ed05d4-05b5-40e7-91dd-c3bda6e7471e%2F4cf676fa-c9ba-446e-ab36-63df3e44753e%2Fd7qfgz9_processed.png&w=3840&q=75)
Transcribed Image Text:Three components are connected to form a system as shown in the accompanying diagram. Because the components in the 2-3 subsystem are connected in parallel, that subsystem will function if at least one of the two individual components functions. For the entire system to
function, component 1 must function and so must the 2-3 subsystem.
2
[마
The experiment consists of determining the condition of each component [S (success) for a functioning component and F (failure) for a nonfunctioning component]. (Enter your answers in set notation. Enter EMPTY or ø for the empty set.)
(a) Which outcomes are contained in the event A that exactly two of the three components function?
A
%3D
(b) Which outcomes are contained in the event B that at least two of the components function?
B =
(c) Which outcomes are contained in the event C that the system functions?
C =
(d) List outcomes in C'.
C' =
List outcomes in A UC.
AUC-
List outcomes in AN C.
ANC=
List outcomes in BU C.
BUC =
List outcomes in B n C.
BnC =
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