Three different methods for assembling a product were proposed by an industrial engineer. To investigate the number of units assembled correctly with each method, 30 employees were randomly selected and randomly assigned to the three proposed methods in such a way that each method was used by 10 workers. The number of units assembled correctly was recorded, and the analysis of variance procedure was applied to the resulting data set. The following results were obtained: SST=10,810; SSTR =4580. a. Set up the ANOVA table for this problem (to 2 decimals but p-value to 4 decimals, if necessary).

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Three different methods for assembling a product were proposed by an industrial engineer. To investigate the number of units assembled correctly with each
method, 30 employees were randomly selected and randomly assigned to the three proposed methods in such a way that each method was used by 10 workers.
The number of units assembled correctly was recorded, and the analysis of variance procedure was applied to the resulting data set. The following results were
obtained: SST=10,810; SSTR =4580.
a. Set up the ANOVA table for this problem (to 2 decimals but p-value to 4 decimals, if necessary).
Source of Variation Sum of Squares Degrees of Freedom Mean Square
Treatments
Error
Total
2
F
The p-value is less than 0.01
What is your conclusion?
Conclude not all means of the three assembly methods are equal
9.87
b.Use a =
0.05 to test for any significant difference in the means for the three assembly methods.
Calculate the value of the test statistic (to 2 decimals).
p-value
.0001
Transcribed Image Text:Three different methods for assembling a product were proposed by an industrial engineer. To investigate the number of units assembled correctly with each method, 30 employees were randomly selected and randomly assigned to the three proposed methods in such a way that each method was used by 10 workers. The number of units assembled correctly was recorded, and the analysis of variance procedure was applied to the resulting data set. The following results were obtained: SST=10,810; SSTR =4580. a. Set up the ANOVA table for this problem (to 2 decimals but p-value to 4 decimals, if necessary). Source of Variation Sum of Squares Degrees of Freedom Mean Square Treatments Error Total 2 F The p-value is less than 0.01 What is your conclusion? Conclude not all means of the three assembly methods are equal 9.87 b.Use a = 0.05 to test for any significant difference in the means for the three assembly methods. Calculate the value of the test statistic (to 2 decimals). p-value .0001
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