Q3(a)Three plain-carbon steel types are: eutectoid, hypoeutectoid, and hypereutectoid can be seenin the Iron-Carbon phase diagram as shown in Figure Q3(a).Explain the effect of heating to 780 °C and slow cooling to 650 °C on these materialtypes for the carbon weight percentages of 0.4%, 0.8% and 1.2%..(i)(ii) Draw the effect of temperature on the microstructure of one plain carbon steel tvpe.(1539* C)2902 F2554 FLiquidL+ AusteniteL+CementiteAustenite2065 "F (1130 C)Eutectic(Ledeburite)Aus, + FerriteAustenite + Cementite(908* C)1666* F1333 F (723 C)K.Eutectoid(pearlite)FerriteFerrite + Cementite0.82.04.36.67Fe,CPercent carbon by weightHypo-eutectoidHyper-eutectoidHypoeutectio - HypereutecticSteelsCastironsFigure Q3(a)Temperature, F

Given : To find : Effect of temperature on microstructure of steel

Three plain-carbon steel types are: eutectoid, hypoeutectoid, and hypereutectoid can be seen in the Iron-Carbon phase diagram as shown in Figure Q3(a). (i) Explain the effect of heating to 780 °C and slow cooling to 650 °C on these material types for the carbon weight percentages of 0.4%, 0.8% and 1.2%.. (ii) Draw the effect of temperature on the microstructure of one plain carbon steel tvpe. (1539° 2802 F 2554 F Liquid L+ Austenite L+Cementite D. Austenite 2065 °F (1130° C) Eutectic (Ledeburite) Aus, + Ferrite Austenite + Cementite (908 C) 1666 F 1333 F (723 C) K. Eutectoid (pearlite) Ferrite Ferrite + Cementite 0.8 2.0 4.3 6.67 Fe,C Percent carbon by weight Hypo- eutectoid Hyper- eutectoid Hypoeutectiom Hypereutectic Steels Castirons Figure Q3(a) Temperature, F

Three plain-carbon steel types are: eutectoid, hypoeutectoid, and hypereutectoid can be seen in the Iron-Carbon phase diagram as shown in Figure Q3(a). (i) Explain the effect of heating to 780 °C and slow cooling to 650 °C on these material types for the carbon weight percentages of 0.4%, 0.8% and 1.2%.. (ii) Draw the effect of temperature on the microstructure of one plain carbon steel tvpe. (1539° 2802 F 2554 F Liquid L+ Austenite L+Cementite D. Austenite 2065 °F (1130° C) Eutectic (Ledeburite) Aus, + Ferrite Austenite + Cementite (908 C) 1666 F 1333 F (723 C) K. Eutectoid (pearlite) Ferrite Ferrite + Cementite 0.8 2.0 4.3 6.67 Fe,C Percent carbon by weight Hypo- eutectoid Hyper- eutectoid Hypoeutectiom Hypereutectic Steels Castirons Figure Q3(a) Temperature, F

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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A hypo-eutectoid steel with composition of 0.5% carbon is heated to 1000°. Using the a iron-carbon phase diagram (also found in the course book, or here https://commons.wikimedia.org/wiki/File:Iron_carbon_phase_diagram.svg (Links to an external site.) (Links to an external site.)) answer the following questions. (a) What phase or phases will be present at 950°C? (b) If temperature is lowered from 950°C, at which temperature (estimate) α phase (Ferrite) will appear? (c) Use the lever rule to estimate how much (wt%) ferrite and how much austenite will exist just above 727 °C? (d) What happens to the austenite if the temperature is lowered below 727 °C? (e) Schematically sketch and label the resulting microstructure.
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