Please calculate enthalpies and the heat of a condenser and evaporator. Thank you Throttle[Ideal Vapor compressionThe amonia leaving condenser isunder cooledby 2K3Condenser900Kpq120 краEvaporator2qRefrigeration?CompressorWe = 5083,48KW[DrawT-S diagram 30[Calculate all the enthalpies]Properties of Ammoniaка krossSI editionThermodynamicsFor engineersAmmoniaappendix 4Mpq600%4(ST =Pumi(7=;= 2= 28= 30Table E-l Saturated AmmoniaSpecific volumem³/kgE Properties of AmmontT, "C-50-46-44-42-40-38EnthalpykJ/kg"P, kPa2440.88 0.00142451.55 0.00143457.69 0.00143964.4271.77 0.0014490.001444-3679.80 0.0014540.0014600.00146588.54-3498,05108.37-320.001470-30 119/550.001476-28 131.64 0.0014810.8059Toh, h2.6254 -44.3 1416.7 1372.42.1140 -26.6 1405.8 1379.21.9032 -17.8 1400.3 1382.51.7170 -8.9 1394.7 1385.81.55210,0 1389.0 1389.01.40858,9 1383.3 1392.21.2757 17.8 1377.6 1395.41.1597 26.8 1371,8 1398.51.056235.71365.9 1401.60.9635 44.7 1360.0 1404.60.880553.61354.0 1407.662.61347.9 1410.5 0.26050.7388 71.6 1341.8 1413.40.6783 80,70.6237 89,718 207.71 0.001510 0.5743 98.8-16 226,45 0,001515 0.5296 107.8-14 246.51 0.001521 0,4889 116.9 1310.0 1427,0-12 267.95 0.001528 0.4520 126.0 1303.5 1429,5-10 290.85 0.001534 0.4185 135.2 1296.8 1432.0-8 315.25 0.001540 0.3878 144,3 1290,1 1434,4-6 341.25 0.001546 0.3599 153.51283.3 1436.8-4 368.90 0.001553 0.3343 162.7-2 398.270,001559 0.3109 171.90 429.44 0.0015662 462.49 0.0015734 497 49 0.001580-26 144.70-24158.78-22 173,930.0014870.0014920.0014980.001504-1335.6 1416.20.29670.33270,3684-20 190.22(1329.3 1419.00.40401322,9 1421.71315.5 1424.40.43931276.4 1439.11259.4 1441.368218.3 1233.2 1451.50.2895 181.1 1252.4 1443.50.2698 190.41255.2 1445,6T0.2517199.61248.01447.60.2351 208.9 1240.6 1449.60.21980.20560.19260 T8050.16930.1590 265.40.1494 274.9534,51 0.001587573,64 0.00159410 614.95 0.00160112 658.52 0,00160814 704,44 0.00161616 752.79 0.00162318 803.66 0.00163120 857.12 0.001639227.6 1225.7 1453.3237.0 1218.1246.4 1210.41455.11456.8255.9 1202.6 1458.51194,7 1460.01186.7 1461.512860 AppE ptg01 INDD 545S₁-0.1942-0.1156-0.0768-0,03820,00000,03800.07570.11320.15040.18730.47440.50930.54400.57855,88405.81015.73725.66525.59420.2240 5.52415.45485.38645.31885,25200.61280.64690,68080.71450.74810.78150.81480.84790.88080.91360.94630.97881.01121.0434290 300EntropykJ/kg.Kupiniping5196.35026.19026.11206.03495,95895.18605.12075.05614.99224.92904.8664596.15616,07466,03525.99675.95895.92205.88585,85045:81565.78155.74815.71535.68315.65155.62055,59005.56005,53055.50155.47305.44495.41735.39015.36335.33694.80454.74324.68254.62234.56274.50374.44515.25994.38715.23504.3295 5.21044.27255.1861421594.15974.10394.04865.31085.28525.13855.11515.0920(Continued)08/10/13 3:52 PM40 150 1

P[1] = 120[kPa] P[2] = 900[kPa] The ideal refrigeration and refrigerant is ammonia. Find the…

Throttle [Ideal Vapor compression Refrigeration? The amonia leaving Condenser is under cooled by 2K Condenser 900kpq 120 кра Evaporati We = 5083148KW 2 9 Compressor Ammonia appendix [Draw T-S diagram 30 [Calculate all the enthalpies] Properties of Ammonia ка kross SI edition Thermodynamics For engineers

Throttle [Ideal Vapor compression Refrigeration? The amonia leaving Condenser is under cooled by 2K Condenser 900kpq 120 кра Evaporati We = 5083148KW 2 9 Compressor Ammonia appendix [Draw T-S diagram 30 [Calculate all the enthalpies] Properties of Ammonia ка kross SI edition Thermodynamics For engineers

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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