timeout timeout Sender Consider the figure below (simplex communication scenario). 23 Seq1, 10 bytes of data Seq2, 10 bytes Seq3, 10 bytes ACK1 ACK2 XA ACK4 Seq4 ACK3 The initial SEQ Number (Seq1) is 567. 1. 123 2. 3. What is Seq2 and Seq3 What is ACK1, ACK2, Ack3 What is Seq4 and ACK4 Receiver 3
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- Compute CBC-MAC for a message of 16 bits, “ABCD” (in Hexa). Assume a block size of 8 bits with an IV=C9 (in hexa). For simplicity, assume the encryption to be a simple XOR of the key with the plaintext. Let the encryption key be D8 (in Hexa). (Hint: Divide the message into blocks of 8 bits each; XOR each block with the previous cipher output; then encrypt this with the key. For the first block, XOR it with IV.This is what my professor said: Items are 4 bytes, pages are 2k, so ~512 items fit on a page. Even if we start in the beginning of a page, the first access will be a miss followed by ~200 hits, then a TLB miss followed by ~500 hits, so the hit rate is ~100%5. Page size 512 means 9 bits of offset and 7 bits of VPN. The offset is just the decimal version of 1 0111 0111 [unsigned] which is 375The offset is 0011 100 which is 28. Is he correct?Computer Science To answer this question, you may need to write a small program. Consider the following case: current cwnd value is 1000 bytes and 1 MSS is 10 bytes (=1 TCP packet carries 10 bytes of payload). With the basic formula, after 1 RTT, the congestion window would be updated to 1010 bytes (1000 + 10). What would be the value of window if ACK clocking is used? It would be a non-integer number, so give value including only two digits after comma
- Consider the following page address stream: 2 1 4 3 5 3 2 4 5 2 1 2 4 3 1 Which of the following causes the most page faults to occur on a machine with 3 frames? Scheme that causes the most faults: a) First in First out b) LRU and FIFO are the same number of faults c) FIFO and Opitimal are the same number of faults d) All have the same number of faults e) Least Recently Used f) No faults occurs g) LRU and Optimal are the same number of faults h) Optimal NUMBER OF FAULTS CAUSED: a)10. The technique of temporarily delaying outgoing acknowledgements so that they can be hooked onto the next outgoing data frame is known as a. Bit stuffing b. Piggy backing c. Pipelining d. BroadcastingAssume you are using any correct plaintext padding method, such as those described in lecture, with a 128-bit (16-byte) block cipher. If you are sending a message that is 184 bytes long, how many padding bytes would you need to add? Justify your answer. For the remaining questions, consider a 4-bit block cipher, described in hexadecimal by the following table: Plaintext Ciphertext Plaintext Ciphertext 0 a 8 e 1 c 9 d 2 f a 0 3 6 b 7 4 3 c 5 5 8 d b 6 4 e 9 7 2 f 1 You can think of this as a simple substitution cipher for hexadecimal digits. There is no “key” other than the table itself.
- Given the logical address 0x 69656, what will be the logical page number issued by a process P? OxD What is the corresponding physical frame number? 15 What is the hexadecimal physical address? I am having trouble to understand how you get hexadecimal physical address answer OxA9656 Your responses should be given in hexadecimal format!a. Compute CBC-MAC for a message of 16 bits, “8642” (in Hexa). Assume a block size of 8 bits with an IV=F1 (in hexa). For simplicity, assume the encryption to be a simple XOR of the key with the plaintext. Let the encryption key be B4 (in Hexa).Suppose the Vole communicates with a printer using the technique of memory-mapped I/O. Suppose also thataddress 0xFF is used to send characters to the printer, and address 0xFE is used to receive information about theprinter’s status. In particular, suppose the least significant bit at the address 0xFE indicates whether the printeris ready to receive another character (with a 0 indicating “not ready” and a 1 indicating “ready”). Starting ataddress 0x00, write a machine language routine that waits until the printer is ready for another character and thensends the character represented by the bit pattern in register 0x5 to the printer.
- **Please do C****C IS different from B** a. Compute CBC-MAC for a message of 16 bits, “8642” (in Hexa). Assume a block size of 8 bits with an IV=F1 (in hexa). For simplicity, assume the encryption to be a simple XOR of the key with the plaintext. Let the encryption key be B4 (in Hexa). (Hint: Divide the message into blocks of 8 bits each; XOR each block with the previous cipher output; then encrypt this with the key. For the first block, XOR it with IV. Details in pages 325-326 Ch.12 of the textbook) b. Suppose Alice computes the Secret prefix MAC (page 322: secret prefix MAC(x) = h(key || x)) for the message ”AM” (in ASCII) with key “G” (in ASCII) that both Alice and Bob know. The hash function that is used is h(x1x2x3)= g(g(x1 XOR x2) XOR x3 ) where each xi is a character represented as 8 bits, and g(x) is a 8-bit string that is equal to the complement of bits in x. For example, g(10110011) = 01001100. The MAC is 8 bits. (8-bit ASCII representation of the characters is given…This question was already asked on Bartleby however the two level table was not created. A computer system uses 16-bit addresses for virtual and physical addresses, and each page and frame has a size of 256 bytes. 1. suppose that the OS uses a two-level page table. Draw the page table using the same structure and logic as the image provided, from an article found online this logic can be anazyed through the link https://sonsh0824.tistory.com/entry/MultiLevel-Page-Table . (Assume that frames 7 through 221 are free, so you can allocate space for the page table there.) In addition, suppose that the page-table directory storage comprises a whole number of consecutive full frames. (For examples: if the directory entry is 2 bytes, the entry’s storage comprises 1 frame; if the directory entry is 260 bytes, the entry’s storage comprises 2 consecutive frames.) 2. What is the size of the two-level page table given in question I(f)? 3. Now, translate the virtual addresses to physical…Q: Consider a system which has Logical Address = 4 GB, Physical Address PA= 64 MB, Page Size = 4 KB, then calculate Number of pages =? Number of frames =? Number of entries in Page Table =? Size of Page Table =?