Titanium(IV) chloride decomposes to form titanium and chlorine, like this: TiCl4(l) -> Ti(s) + 2Cl2(g) At a certain temperature, a chemist finds that a 8.9 L reaction vessel containing a mixture of titaniur(IV) chloride, titanium, and chlorine at equilibrium has the following composition: compound amount TiCl 4.02 g Ti 2.06 g Cl2 2.30 g Calculate the value of the equilibrium constant K, for this reaction, Round your answer to 2 significant digits.
Titanium(IV) chloride decomposes to form titanium and chlorine, like this: TiCl4(l) -> Ti(s) + 2Cl2(g) At a certain temperature, a chemist finds that a 8.9 L reaction vessel containing a mixture of titaniur(IV) chloride, titanium, and chlorine at equilibrium has the following composition: compound amount TiCl 4.02 g Ti 2.06 g Cl2 2.30 g Calculate the value of the equilibrium constant K, for this reaction, Round your answer to 2 significant digits.
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.23PAE
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Question
Titanium(IV) chloride decomposes to form titanium and chlorine, like this:
TiCl4(l) -> Ti(s) + 2Cl2(g)
At a certain temperature, a chemist finds that a 8.9 L reaction vessel containing a mixture of titaniur(IV) chloride, titanium, and chlorine at equilibrium has the following composition:
compound amount
TiCl 4.02 g
Ti 2.06 g
Cl2 2.30 g
Calculate the value of the equilibrium constant K, for this reaction, Round your answer to 2 significant digits.
Transcribed Image Text:Titanium(IV) chloride decomposes to form titanium and chlorine, like this:
TIC4(1)→Ti(s)+2C2(g)
At a certain temperature, a chemist finds that a 8.9 L reaction vessel containing a mixture of titanium(IV) chloride, titanium, and chlorine at equilibrium has the
following composition:
compound amount
TICl4
4.02 g
Ti
2.06 g
C2
2.30g
Calculate the value of the equilibrium constant K for this reaction, Round your answer to 2 significant digits.
K¸ = 0
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