To 2.00 L of 0.445 M HCI, you add 3.88L of a second HCI solution of an unknown concentration. The resulting solution is 0.974 M. Assuming the volumes are additive, calculate the molarity of the second HCl .solution

Fundamentals Of Analytical Chemistry
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Chapter10: Effect Of Electrolytes On Chemical Equilibria
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Problem 10.13QAP
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الوقت المتبقي
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To 2.00 L of 0.445 M HCI,
you add 3.88 L of a second
HCl solution of an unknown
concentration. The resulting
solution is 0.974 M.
Assuming the volumes are
additive, calculate the
molarity of the second HCl
.solution
Transcribed Image Text:1:ov O "ll ZAIN IQ ..ester Exam → < > الوقت المتبقي ... To 2.00 L of 0.445 M HCI, you add 3.88 L of a second HCl solution of an unknown concentration. The resulting solution is 0.974 M. Assuming the volumes are additive, calculate the molarity of the second HCl .solution
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