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One way to remove lead from water is to add a source of iodide ion so that the lead will precipitate out of solution. For a solution of lead (II) nitrate, this can be done by reacting it with sodium iodide. What volume of 0.206 M sodium iodide solution would be required to react completely with 106.8 mL of a solution with a lead concentration of 0.159 M? Give your answer in L.

One way to remove lead from water is to add a source of iodide ion so that the lead will precipitate out of solution. For a solution of lead (II) nitrate, this can be done by reacting it with sodium iodide. What volume of 0.206 M sodium iodide solution would be required to react completely with 106.8 mL of a solution with a lead concentration of 0.159 M? Give your answer in L.

Principles of Modern Chemistry
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter11: Solutions
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Problem 66AP: Relative solubilities of salts in liquid ammonia can differsignificantly from those in water. Thus,...
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One way to remove lead from water is to add a source of iodide ion so that the lead will precipitate out of solution. For a solution of lead (II) nitrate, this can be done by reacting it with sodium iodide. What volume of 0.206 M sodium iodide solution would be required to react completely with 106.8 mL of a solution with a lead concentration of 0.159 M? Give your answer in L.
Transcribed Image Text:One way to remove lead from water is to add a source of iodide ion so that the lead will precipitate out of solution. For a solution of lead (II) nitrate, this can be done by reacting it with sodium iodide. What volume of 0.206 M sodium iodide solution would be required to react completely with 106.8 mL of a solution with a lead concentration of 0.159 M? Give your answer in L.
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