To a 25.00 mL volumetric flask, a lab technician adds a 0.300 g sample of a weak monoprotic acid, HA, and dilutes to the mark with distilled water. The technician then titrates this weak acid solution with 0.0816 M KOH. She reaches the endpoint after adding 48.85 mL of the KOH solution. Determine the number of moles of the weak acid in the solution. moles of weak acid: mol Determine the molar mass of the weak acid. molar mass = g/mol After the technician adds 15.85 mL of the KOH solution, the pH of the mixture is 4.31. Determine the pK, of the weak acid. pK, =

Chemistry: Principles and Reactions
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Author:William L. Masterton, Cecile N. Hurley
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Chapter4: Reactions In Aqueous Solution
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To a 25.00 mL volumetric flask, a lab technician adds a 0.300 g sample of a weak monoprotic acid, HA, and dilutes to the mark
with distilled water. The technician then titrates this weak acid solution with 0.0816 M KOH. She reaches the endpoint after
adding 48.85 mL of the KOH solution.
Determine the number of moles of the weak acid in the solution.
moles of weak acid:
mol
Determine the molar mass of the weak acid.
molar mass =
g/mol
After the technician adds 15.85 mL of the KOH solution, the pH of the mixture is 4.31. Determine the pK, of the weak acid.
pK, =
80
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Transcribed Image Text:on 7 of 21 To a 25.00 mL volumetric flask, a lab technician adds a 0.300 g sample of a weak monoprotic acid, HA, and dilutes to the mark with distilled water. The technician then titrates this weak acid solution with 0.0816 M KOH. She reaches the endpoint after adding 48.85 mL of the KOH solution. Determine the number of moles of the weak acid in the solution. moles of weak acid: mol Determine the molar mass of the weak acid. molar mass = g/mol After the technician adds 15.85 mL of the KOH solution, the pH of the mixture is 4.31. Determine the pK, of the weak acid. pK, = 80 DII DD F3 F4 F5 FB F9 F10 F11 F12 2$ & 4 5 8 6. %3D de R Y U 10 F G K ww
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