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To evaluate in auditors might be helped in etermining the chances of fraud if they carefully measure cash now, samples of midlevel auditors from CPA firms were asked to indicate the chance of material fraud on a scale from 0 to 100 for a case. A random sample of 36 auditors used the cash-flow information. Their mean assessment was 35.51, and the sample standard deviation was 24.14. For an independent random sample of 36 auditors not using the cash-flow information, the sample mean and standard deviation were, respectively, 40.58 and 29.18. Assuming that the two population distributions are normal with equal variances, test against a two-sided alternative the null hypothesis that the population means are equal. (Use α = 0.05.) Click the icon to view a table of critical values for the Student's t-distribution. Let μx be the mean assessment for auditors who measured cash flow and μy be the mean assessment for auditors not using the cash-flow information. Determine the null and alternative hypotheses. Choose the correct answer below. A. Ho: Hx-Hy = 0 H₁: Hx-Hy ≤0 0 O D. Ho: Hx - Hy=( H₁: Hx-Hy <0 B. Ho: Hx-Hy = 0 H₁: Hx-Hy 20 O E. Ho: Hx -Hy #0 H₁: Hx-Hy = 0 OC. Ho: Hx-Hy = 0 H₁: Hx-Hy >0 OF. Ho: Hx-Hy = 0 H₁: Hx-Hy #0

To evaluate in auditors might be helped in etermining the chances of fraud if they carefully measure cash now, samples of midlevel auditors from CPA firms were asked to indicate the chance of material fraud on a scale from 0 to 100 for a case. A random sample of 36 auditors used the cash-flow information. Their mean assessment was 35.51, and the sample standard deviation was 24.14. For an independent random sample of 36 auditors not using the cash-flow information, the sample mean and standard deviation were, respectively, 40.58 and 29.18. Assuming that the two population distributions are normal with equal variances, test against a two-sided alternative the null hypothesis that the population means are equal. (Use α = 0.05.) Click the icon to view a table of critical values for the Student's t-distribution. Let μx be the mean assessment for auditors who measured cash flow and μy be the mean assessment for auditors not using the cash-flow information. Determine the null and alternative hypotheses. Choose the correct answer below. A. Ho: Hx-Hy = 0 H₁: Hx-Hy ≤0 0 O D. Ho: Hx - Hy=( H₁: Hx-Hy <0 B. Ho: Hx-Hy = 0 H₁: Hx-Hy 20 O E. Ho: Hx -Hy #0 H₁: Hx-Hy = 0 OC. Ho: Hx-Hy = 0 H₁: Hx-Hy >0 OF. Ho: Hx-Hy = 0 H₁: Hx-Hy #0

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 7PPS
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To evaluate if auditors might be helped in determining the chances of fraud if they carefully measure cash flow, samples of midlevel auditors from CPA firms were asked to indicate the chance of material fraud on a scale from 0 to 100 for a case. A random sample of 36 auditors used the cash-flow information. Their mean assessment was 35.51, and the sample standard deviation was 24.14. For an independent random sample of 36 auditors not using the cash-flow information, the sample mean and standard deviation were, respectively, 40.58 and 29.18. Assuming that the two population distributions are normal with equal variances, test against a two-sided alternative the null hypothesis that the population means are equal. (Use α = 0.05.) Click the icon to view a table of critical values for the Student's t-distribution. Let Hx be the mean assessment for auditors who measured cash flow and μy be the mean assessment for auditors not using the cash-flow information. Determine the null and alternative hypotheses. Choose the correct answer below. O A. Ho: Hx-Hy = 0 H₁: Hx-Hy ≤0 = 0 O D. Ho: Hx-Hy = H₁: Hx-Hy <0 B. Hoi Hx Hy = 0 H₁: Hx - Hy ² ≥0 E. Ho: Hx - Hy#0 H₁: Hx-Hy=0 C. Ho: Mx Hy = 0 H₁: Hx-Hy >0 OF. Ho: Hx-Hy = 0 H₁: Hx-Hy #0
Transcribed Image Text:To evaluate if auditors might be helped in determining the chances of fraud if they carefully measure cash flow, samples of midlevel auditors from CPA firms were asked to indicate the chance of material fraud on a scale from 0 to 100 for a case. A random sample of 36 auditors used the cash-flow information. Their mean assessment was 35.51, and the sample standard deviation was 24.14. For an independent random sample of 36 auditors not using the cash-flow information, the sample mean and standard deviation were, respectively, 40.58 and 29.18. Assuming that the two population distributions are normal with equal variances, test against a two-sided alternative the null hypothesis that the population means are equal. (Use α = 0.05.) Click the icon to view a table of critical values for the Student's t-distribution. Let Hx be the mean assessment for auditors who measured cash flow and μy be the mean assessment for auditors not using the cash-flow information. Determine the null and alternative hypotheses. Choose the correct answer below. O A. Ho: Hx-Hy = 0 H₁: Hx-Hy ≤0 = 0 O D. Ho: Hx-Hy = H₁: Hx-Hy <0 B. Hoi Hx Hy = 0 H₁: Hx - Hy ² ≥0 E. Ho: Hx - Hy#0 H₁: Hx-Hy=0 C. Ho: Mx Hy = 0 H₁: Hx-Hy >0 OF. Ho: Hx-Hy = 0 H₁: Hx-Hy #0
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