To Fahrenheit ['F] = ([°C] x 1.8) + 32 To Kelvin [K] = [°C] + 273.15 %3D o Celsius [°C] = [K] – 273.15 te the molarity of a solution of 297.6 g of CUSO4

Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter11: Solutions
Section: Chapter Questions
Problem 10P
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#5
Fahrenheit
To Celsius
[°C] = ([°F] – 32) + 1.8
Celsius:
To Fahrenheit
['F] = ([°C] x 1.8) + 32
To Kelvin
[K] = [°C] + 273.15
Kelvin to Celsius
['C] = [K] – 273.15
a) Calculate the molarity of a solution of 297.6 g of CuSO4 in 1.80x10- mL of aqueous solution.
b) What is the density of the solution, assuming the total volume of solution comes from water?
Transcribed Image Text:Fahrenheit To Celsius [°C] = ([°F] – 32) + 1.8 Celsius: To Fahrenheit ['F] = ([°C] x 1.8) + 32 To Kelvin [K] = [°C] + 273.15 Kelvin to Celsius ['C] = [K] – 273.15 a) Calculate the molarity of a solution of 297.6 g of CuSO4 in 1.80x10- mL of aqueous solution. b) What is the density of the solution, assuming the total volume of solution comes from water?
To Kelvin
[K] = [°C] + 2
Ivin to Celsius
['C] = [K] – 2
1.04 M
1.65 M
2.79 M
3.87 M
4.15 M
6.18 M
7.98 M
10.4 M
1.12 g/mL
1.65 g/mL
2.65 g/mL
3.12 g/mL
3.51 g/mL
4.12 g/mL
7.89 g/mL
none of these
Transcribed Image Text:To Kelvin [K] = [°C] + 2 Ivin to Celsius ['C] = [K] – 2 1.04 M 1.65 M 2.79 M 3.87 M 4.15 M 6.18 M 7.98 M 10.4 M 1.12 g/mL 1.65 g/mL 2.65 g/mL 3.12 g/mL 3.51 g/mL 4.12 g/mL 7.89 g/mL none of these
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