To “see” such an orbiting electron by using a light microscope to measure the electron’s presumed orbital position with a precision of 10 pm (1 p = 1 pico = 10^-12), (a) What would be the photon energy of this light? (b) How much energy would such a photon impart to an electron in a head-on collision?

University Physics Volume 3
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ISBN:9781938168185
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Chapter6: Photons And Matter Waves
Section: Chapter Questions
Problem 142AP: A photon of energy 5.0 keV collides with a stationary electron and is scattered at an angle of 60°....
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To “see” such an orbiting electron by using a light microscope to measure the electron’s presumed
orbital position with a precision of 10 pm (1 p = 1 pico = 10^-12), (a) What would be the photon energy of this light? (b) How much energy would such a photon impart to an electron in a head-on collision? 
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