Treating 1,3-butadiene with 1 mole of HBr gives a mixture of two isomeric products. Br CH2=CH-CH=CH, + H-Br - CH,— CH—CH— CH, + CH,—Сн— СН—CH, — Вr 1,3-Butadiene 3-Bromo-1-butene 1-Bromo-2-butene (a racemic mixture) Propose a mechanism that accounts for the formation of these two products.

Treating 1,3-butadiene with 1 mole of HBr gives a mixture of two isomeric products. Br CH2=CH-CH=CH, + H-Br - CH,— CH—CH— CH, + CH,—Сн— СН—CH, — Вr 1,3-Butadiene 3-Bromo-1-butene 1-Bromo-2-butene (a racemic mixture) Propose a mechanism that accounts for the formation of these two products.

Organic Chemistry

9th Edition

ISBN:9781305080485

Author:John E. McMurry

Publisher:John E. McMurry

Chapter11: Reactions Of Alkyl Halides: Nucleophilic Substitutions And Eliminations

Section11.SE: Something Extra

Problem 34MP: Reaction of iodoethane with CN- yields a small amount of isonitrile, CH3CH2Nâ‰¡C, along with the...

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