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Treating ethers with hydrobromic acid(hbr) cleaves the ethers into two alkyl bromides. Using the ether product that u get in the pic i posted deduce the identity of both of the alkyl bromide products produced when it is treated with HBr. Draw the two mechanism for their formation? Thank u

Treating ethers with hydrobromic acid(hbr) cleaves the ethers into two alkyl bromides. Using the ether product that u get in the pic i posted deduce the identity of both of the alkyl bromide products produced when it is treated with HBr. Draw the two mechanism for their formation? Thank u

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Treating ethers with hydrobromic acid(hbr) cleaves the ethers into two alkyl bromides. Using the ether product that u get in the pic i posted deduce the identity of both of the alkyl bromide products produced when it is treated with HBr. Draw the two mechanism for their formation? Thank u 

12:24 bartleby.com/questi SEARCH H3C- CH3 C H3C- CH3 tert-butyl alcohol Step 3 -OH + HCI H3C- CH3 OH + H CH3 tert-butyl alcohol ASK C,H,OH (excess) CH3 Tertiary carbocation C₂H,OH (excess) CH3 tert-butyl chloride H3C- CH3 + C₂H5O CI CH3 H -C CH3 Mechanism: This reaction proceeds via SN1 mechanism. Step 1: In this mechanism, the reaction. proceeds via the formation of a carbocation after the removal of the leaving group. OH is not a good leaving group but after protonation, H₂O is a very good leaving group. O WAS THIS HELPFUL? ••+H CHAT H + H3C- -H₂O CH3 H3C- -C-O CH3 H3C- ethyl isopropyl ether Step 2: In the second step, the nucleophile then attacks the carbocation. CH3 | 78% 6 CH3 CH3 -C₂H5 CH3 Tertiary carbocation < CH3 C C₂H5 ethyl isopropyl ether √x
Transcribed Image Text:12:24 bartleby.com/questi SEARCH H3C- CH3 C H3C- CH3 tert-butyl alcohol Step 3 -OH + HCI H3C- CH3 OH + H CH3 tert-butyl alcohol ASK C,H,OH (excess) CH3 Tertiary carbocation C₂H,OH (excess) CH3 tert-butyl chloride H3C- CH3 + C₂H5O CI CH3 H -C CH3 Mechanism: This reaction proceeds via SN1 mechanism. Step 1: In this mechanism, the reaction. proceeds via the formation of a carbocation after the removal of the leaving group. OH is not a good leaving group but after protonation, H₂O is a very good leaving group. O WAS THIS HELPFUL? ••+H CHAT H + H3C- -H₂O CH3 H3C- -C-O CH3 H3C- ethyl isopropyl ether Step 2: In the second step, the nucleophile then attacks the carbocation. CH3 | 78% 6 CH3 CH3 -C₂H5 CH3 Tertiary carbocation < CH3 C C₂H5 ethyl isopropyl ether √x
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