Treatment of hydroxylamine (H₂NOH) with an excess of Fe (III) results in the formation of N₂O and an equivalent amount of Fe (II): 2 H₂NOH + 4 Fe³+ N₂O(g) + 4 Fe2+ + 14 H+ + H₂O Calculate the molar concentration of an H₂NOH solution if the Fe (II) produced by treatment of a 34.60 --mL aliquot required 12.57 mL of 0.0232 M K2Cr207. Cr₂O72- + 6 Fe²+ + 12 H+ 2 Cr³+ + 6 Fe 3+ + 7 H₂O

Chemistry & Chemical Reactivity
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ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter17: Principles Of Chemical Reactivity: Other Aspects Of Aqueous Equilibria
Section: Chapter Questions
Problem 104IL: You will often work with salts of Fe3+, Pb2+, and Al3+ in the laboratory. (All are found in nature,...
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Treatment of hydroxylamine (H₂NOH) with an excess of Fe (III) results in the formation of N₂O and an
equivalent amount of Fe (II):
2 H₂NOH + 4 Fe³+ N₂O(g) + 4 Fe2+ + 14 H+ + H₂O
Calculate the molar concentration of an H₂NOH solution if the Fe (II) produced by treatment of a 34.60
-mL aliquot required 12.57 mL of 0.0232 M K₂Cr207.
3+
Cr₂O72- + 6 Fe2+ + 12 H+ 2 Cr³+ + 6 Fe + 7 H₂O
Transcribed Image Text:Treatment of hydroxylamine (H₂NOH) with an excess of Fe (III) results in the formation of N₂O and an equivalent amount of Fe (II): 2 H₂NOH + 4 Fe³+ N₂O(g) + 4 Fe2+ + 14 H+ + H₂O Calculate the molar concentration of an H₂NOH solution if the Fe (II) produced by treatment of a 34.60 -mL aliquot required 12.57 mL of 0.0232 M K₂Cr207. 3+ Cr₂O72- + 6 Fe2+ + 12 H+ 2 Cr³+ + 6 Fe + 7 H₂O
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