Treatment of the polymer shown below with aqueous 6 molar hydrochloric acid at 80 °C leads to which products? Check the correct answer. HN 0 1.1,6 Hexanediol, carbon dioxide, and the dihydrochloride of the aromatic diamine. O 2 A disocyanate and 1,6-hexanediol. 03.1,6-Hexanediol, phosgene (COCz, and the dihydrochloride of the aromatic diamine. 0 4. The aromatic diamine, urethane, and 1,6-hexanediol.

Organic Chemistry
8th Edition
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Chapter11: Ethers, Epoxides, And Sulfides
Section: Chapter Questions
Problem 11.42P
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Treatment of the polymer shown below with aqueous 6 molar hydrochloric acid at 80 °C leads to which products? Check the correct answer.
HN'
O 1.1,6-Hexanediol, carbon dioxide, and the dihydrochloride of the aromatic diamine.
2. A diisocyanate and 1,6-hexanediol.
O 3. 1,6-Hexanediol, phosgene (COC2), and the dihydrochloride of the aromatic diamine.
O 4. The aromatic diamine, urethane, and 1,6-hexanediol.
Transcribed Image Text:Treatment of the polymer shown below with aqueous 6 molar hydrochloric acid at 80 °C leads to which products? Check the correct answer. HN' O 1.1,6-Hexanediol, carbon dioxide, and the dihydrochloride of the aromatic diamine. 2. A diisocyanate and 1,6-hexanediol. O 3. 1,6-Hexanediol, phosgene (COC2), and the dihydrochloride of the aromatic diamine. O 4. The aromatic diamine, urethane, and 1,6-hexanediol.
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