Trial 1 Trial 2 Trial 3 Moles HCI (mols) (Use the balanced equation to 7. create a mole ratio to convert moles of NaOH to moles of HCI) 0.00267168 0.00271584 0.00272688 Part 6 of 10 Trial 1 Trial 2 Trial 3 0.02420 0.0284 Volume of HCL (L) 8. |(1L = 1000 mL) 0.02500 * 0.02500 e 0.02500 a 0.02500 Part 7 of 10 Trial 1 Trial 2 Trial 3 Molarity HCl (M) moles solute 9. (molarity liters solution

Trial 1 Trial 2 Trial 3 Moles HCI (mols) (Use the balanced equation to 7. create a mole ratio to convert moles of NaOH to moles of HCI) 0.00267168 0.00271584 0.00272688 Part 6 of 10 Trial 1 Trial 2 Trial 3 0.02420 0.0284 Volume of HCL (L) 8. |(1L = 1000 mL) 0.02500 * 0.02500 e 0.02500 a 0.02500 Part 7 of 10 Trial 1 Trial 2 Trial 3 Molarity HCl (M) moles solute 9. (molarity liters solution

Chemistry: Principles and Reactions

8th Edition

ISBN:9781305079373

Author:William L. Masterton, Cecile N. Hurley

Publisher:William L. Masterton, Cecile N. Hurley

Chapter10: Solutions

Section: Chapter Questions

Problem 49QAP: Caffeine is made up of 49.5% C, 5.2% H, 16.5% O, and 28.9% N. A solution made up of 8.25 g of...

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