Type it out please Mole of AgCl =(mole = mass /molar mass)Calculate mole of AGNO, in the 10 mL unknown solution based on the following reactionequation:NaClag) + AGNO3(aq)NaNO3(aq) + AgCls)(hint,Mole of AgNO3 in the 10 mL unknown solution =use the coefficient ratio) Watch the Introductory Video and Support Information on the upper left to learn how touse this virtual lab.i.i.Place a bottle of 0.1 M NaCl solution, the unknown AGNO, solution, a 250 mL Erlenmeyerflask, a 10 mL pipette, and a burette (in Glassware→Other) on the workbench. If thebench is said to be too full, set the items along the right side the bench to save space.Record the volume of the original unknown AGNO, solution in the Data sheet.Workbench 1Unknown AgNO,0.IMNaCI100 00 ml25s.0°C52.500 ml 25.0c250 ml Flask0000 ml25.OC10 ml Pipette00000 m 25.0c50 ml Burette0.0000 mt250cii.Transfer 50 mL of 0.1 M NaCl solution into the burette.Withdraw 10 mL of the unknown AGNO, solution into the pipette and transfer the solutioninto the empty Erlenmeyer flask.V.Deliver 1 mL of the 0.1 M NaCl solution from the burette into the 10 mL unknown AGNO,solution. Pay attention to mass of AgCl displayed in the information windowInformationName 250 m FlakVolume 11007mSpecies (s)ams00143310 m PotteTemperature 25.00c0000e5oon ANo,s0025.0CPredset 7.00From 50 m Bute to o mPa100 m antened250m Flask110075ocso00025ocRepeat addition of 1 mL of the 0.1 M NaCl solution from the burette into the unknownsolution until the mass of AgCl doesn't change any more. Record the mass of theprecipitate A9CI on the Data Sheet.vi.

Here we are titrating an unknown AgNO3(aq) sample with NaCl(aq) to find the moles of AgNO3(s) in the…

Mole of AgCl = (mole = mass /molar mass) %3D Calculate mole of AGNO, in the 10 mL unknown solution based on the following reaction equation: NaClag) + AGNO3(aq) NANO3(ag) + AgCl) (hint, Mole of AGNO, in the 10 mL unknown solution = use the coefficient ratio)

Mole of AgCl = (mole = mass /molar mass) %3D Calculate mole of AGNO, in the 10 mL unknown solution based on the following reaction equation: NaClag) + AGNO3(aq) NANO3(ag) + AgCl) (hint, Mole of AGNO, in the 10 mL unknown solution = use the coefficient ratio)

Chemistry: Principles and Reactions

8th Edition

ISBN:9781305079373

Author:William L. Masterton, Cecile N. Hurley

Publisher:William L. Masterton, Cecile N. Hurley

Chapter3: Mass Relations In Chemistry; Stoichiometry

Section: Chapter Questions

Problem 23QAP

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Question

Type it out please

Mole of AgCl =
(mole = mass /molar mass)
Calculate mole of AGNO, in the 10 mL unknown solution based on the following reaction
equation:
NaClag) + AGNO3(aq)
NaNO3(aq) + AgCls)
(hint,
Mole of AgNO3 in the 10 mL unknown solution =
use the coefficient ratio)

Watch the Introductory Video and Support Information on the upper left to learn how to
use this virtual lab.
i.
i.
Place a bottle of 0.1 M NaCl solution, the unknown AGNO, solution, a 250 mL Erlenmeyer
flask, a 10 mL pipette, and a burette (in Glassware→Other) on the workbench. If the
bench is said to be too full, set the items along the right side the bench to save space.
Record the volume of the original unknown AGNO, solution in the Data sheet.
Workbench 1
Unknown AgNO,
0.IMNaCI
100 00 ml25s.0°C
52.500 ml 25.0c
250 ml Flask
0000 ml25.OC
10 ml Pipette
00000 m 25.0c
50 ml Burette
0.0000 mt250c
ii.
Transfer 50 mL of 0.1 M NaCl solution into the burette.
Withdraw 10 mL of the unknown AGNO, solution into the pipette and transfer the solution
into the empty Erlenmeyer flask.
V.
Deliver 1 mL of the 0.1 M NaCl solution from the burette into the 10 mL unknown AGNO,
solution. Pay attention to mass of AgCl displayed in the information window
Information
Name 250 m Flak
Volume 11007m
Species (s)
ams
001433
10 m Potte
Temperature 25.00c
0000e5oon ANo,
s0025.0C
Predse
t 7.00
From 50 m Bute to o mPa
100 m antened
250m Flask
110075oc
so00025oc
Repeat addition of 1 mL of the 0.1 M NaCl solution from the burette into the unknown
solution until the mass of AgCl doesn't change any more. Record the mass of the
precipitate A9CI on the Data Sheet.
vi.

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