Tweedledum and Tweedledee are carrying a uniform wooden board that is LLL = 3.00 mm long and has a weight of w = 160 N. Tweedledum applies an upward force of magnitude F1 = 60.0 NN at the left end of the board. Which of the following is the correct equation for Στ for the given rotation axis? All rotation axes lie on the x-axis and torques that would cause a counterclockwise rotation are positive. Enter the letter(s) of the correct equation(s) in alphabetical order. For instance, if you thought that choices A, B, and D were correct, you would enter ABD.
Tweedledum and Tweedledee are carrying a uniform wooden board that is LLL = 3.00 mm long and has a weight of w = 160 N. Tweedledum applies an upward force of magnitude F1 = 60.0 NN at the left end of the board. Which of the following is the correct equation for Στ for the given rotation axis? All rotation axes lie on the x-axis and torques that would cause a counterclockwise rotation are positive. Enter the letter(s) of the correct equation(s) in alphabetical order. For instance, if you thought that choices A, B, and D were correct, you would enter ABD.
University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter10: Fixed-axis Rotation
Section: Chapter Questions
Problem 48P: An ultracentrifuge accelerates from to 100,000 rpm in 2.00 min. (a) What is the average angular...
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Tweedledum and Tweedledee are carrying a uniform wooden board that is LLL = 3.00 mm long and has a weight of w = 160 N. Tweedledum applies an upward force of magnitude F1 = 60.0 NN at the left end of the board.
Which of the following is the correct equation for Στ for the given rotation axis? All rotation axes lie on the x-axis and torques that would cause a counterclockwise rotation are positive.
Enter the letter(s) of the correct equation(s) in alphabetical order. For instance, if you thought that choices A, B, and D were correct, you would enter ABD.
Answer Choices:
Axis of Rotation | Et | |
A | x=0 | (1/2)wL+F2d=0 |
B | x=L | (1/2)wL-F2(L-d)-F1L=0 |
C | x=0 | (-1/2)wL+F2d=0 |
D | x=d | -F1d-F2(d-(1/2)L)=0 |
E | x=(1/2)L | (-1/2)F1L+F2(d-(1/2)L) |
F | x=(1/2)L | (1/2)F1L+F2(d-(1/2)L) |
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