Two blocks slide on a collision course across a frictionless surface, as in the figure. The resulting collision is inelastic. The first block has mass  M = 1.20 kg  and is initially sliding due north at a speed of  Vi = 9.15 m/s.  The second block has mass  m = 7.40 ✕ 10−2 kg  and is initially sliding at a speed of  vi = 13.5 m/s  directed at an angle  θ = 31.5°  south of east. Immediately after the inelastic collision, the second block is observed sliding at  vf = 5.15 m/s  in a direction of  ϕ = 17.5°  north of east.   Determine the components of the first block's velocity after the collision. Vxf  =    Vyf  =

Principles of Physics: A Calculus-Based Text
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Author:Raymond A. Serway, John W. Jewett
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Chapter8: Momentum And Collisions
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Two blocks slide on a collision course across a frictionless surface, as in the figure. The resulting collision is inelastic. The first block has mass 

M = 1.20 kg

 and is initially sliding due north at a speed of 

Vi = 9.15 m/s.

 The second block has mass 

m = 7.40 ✕ 10−2 kg

 and is initially sliding at a speed of 

vi = 13.5 m/s

 directed at an angle 

θ = 31.5°

 south of east. Immediately after the inelastic collision, the second block is observed sliding at 

vf = 5.15 m/s

 in a direction of 

ϕ = 17.5°

 north of east.

 

Determine the components of the first block's velocity after the collision.

Vxf  =   
Vyf  = 
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