Two cylindrical rods AB and BC are welded together at B and loaded as shown. Knowing that the average normal stress must not exceed 175 MPa in rod AB and 150 MPa in rod BC, determine the smallest allowable values of d1 and d2. 300 mm 250 mm B C 40 kN -d₂ 30 kN
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- Two solid cylindrical rods (1) and (2) are joined together at flange B and loaded as shown. If F1 = 19 kips, F2 = 33 kips, and the normal stress in each rod must be limited to 29 ksi, determine the minimum diameter d2 required for rod (2).A rigid plate C is used to transfer a 20-kip load P to a steel (E = 30,000 ksi) rod A and to an aluminum alloy (E = 10,000 ksi) pipe B as shown. The supports at the top of the rod and the bottom of the pipe are rigid, and the materials were unstressed before the load was applied. The cross-sectional areas of rods A and pipe B are 0.80 in2 and 3.00 in2 respectively. Determine The normal stress in rod A in ksi, The normal stress in pipe B in ksi and The displacement of plate C in inches. Note: Draw the Free Body Diagram, include the units/dimensions, use the proper formula and round-off all the answers and final answers to 5 decimal places.Link BD consists of a single wooden member 39.9 mm wide and 19.9 mm thick. Knowing that each pin has a 13.4-mm diameter, determine the maximum value of the average normal stress (in MPa) in link BD if θ= 0° and P = 26.2. Round off the final aswer to three decimal places.
- An aluminum alloy cylinder (2) is clamped between rigid heads by two steel bolts (1), as shown. The steel [E = 200 GPa; α1 = 11.7 × 10−6/°C] bolts have a diameter of 19 mm. The aluminum alloy [E = 70 GPa; α2 = 23.6 × 10−6/°C] cylinder has an outside diameter of 160 mm and a wall thickness of 9 mm. Assume that a = 700 mm, b = 810 mm, and c = 325 mm. If the temperature of this assembly changes by ΔT = 60°C, determine(a) the normal stress in the aluminum cylinder.(b) the normal strain in the aluminum cylinder.(c) the normal strain in the steel bolts.A thin cylinder of length 2.5m and diameter 1.0 m is made from 3mm steel plates. Ifa gas is filled in the cylinder at a pressure of 750 kN/m2(gauge). Take E = 210 GPaand ν = 0.3 for steel, determine(i) the hoop stress and longitudinal stress in the wall of the cylinder(ii) the maximum shear stress in the plane of above two stresses(iii) change in diameter of cylinder due to the internal pressure of gas(iv) change in of the cylinder(v) change in volume of the cylinderAn aluminum tube with the hexagonal cross section shown is 2.5 ft long andhas a constant wall thickness of 0.080 in. Find (a) the largest torque that the tube cancarry if the shear stress is limited to 7200 psi; and (b) the angle of twist caused by thistorque. Use G = 4 * 10^6 psi for aluminum.
- Segment AB of the bar is a tube with an outer diameter of d1 and a wall thickness of 0.125 in. Segment BC is a solid rod of diameter d2. The average normal stresses must not exceed 3400 psi in rod AB and 6500 in rod BC, respectively. Use P1 = 3,650 lb. and P2 = 5,550 lb. a. Determine the smallest allowable value of d1 (in inches). Round-off to 2-decimal places. b. Determine the smallest allowable value of d2 (in inches). Round-off to 2-decimal places.PLEASE ANSWER ASAP TY! a) Determine the cross-sectional area of the structural tube (in mm2) b) Determine moment of inertia of the cross-section about the neutral axis (in mm4) c) What is the maximum normal stress at point K (in MPa)? Include negative sign if compressive. d) What is the axial stress at section H-K (in MPa)? Include negative sign if compressive. e) What is the flexural stress at section H-K (in MPa)? f) What is the maximum normal stress at point H (in MPa)? Include negative sign if compressive.Determine the average normal stress in each rod if T2=400∘F Calculate the new length of the aluminum segment.
- The following system is made up of two rigid bars with a 5cm x 5cm section and they are made of A-36 steel. Also, the pins are 1 cm in diameter and are made of 304 stainless steel. A distributed load of 200 N/m is applied to bar AB. 1. Determine the general stresses at points A, B, and C caused by the distributed load on AB and perform the stress transformation. 2. Calculate the failure theory according to Von Mises.the 12 kn m torque is applied to the free end of the 6-m steel shaft. the angle of rotation of the shaft is to be limited to 3 degrees. find the diameter d of the smallest shaft that can be used. What will be the maximum shear stress in the shaft? Use G=83GPa for steelThe light rigid bar ABCD shown is pinned at B and connected to two vertical rods. Assuming that the bar was initially horizontal and the rods stress-free, determine the stress in each rod after the load after the load P = 30 kips is applied.