Two flasks have the same gas at the same initial temperature T and pressure P. The volume V of the flask #1 is much bigger than the volume V2 of the second flask (Vi > V) The flasks are connected by a narrow glass tube which has a drop of liquid mercury. Because the pressure in each flask is the same the drop of mercury is at equilibrium exactly in the middle of the glass tube. Would the drop of mercury move to either side if both flasks were heated up to the same higher temperature Thigh? The volume of the glass tube is negligibly small in comparison to the volume of flasks. Therefore, the change of the position for the mercury drop simply serves as an indicator of the pressure change between flask #1 and 2. For example, if the mercury drop moves from the center to the flask #2 it means that pressure in flask #1 > pressure in flask #2. Circle the correct answer below and support it with your calculations. Glass tube with a mercury drop #2 #1 Answer: The drop of mercury will: a) move to flask #1 ; b) move to flask #2; c) stay at the center;
Two flasks have the same gas at the same initial temperature T and pressure P. The volume V of the flask #1 is much bigger than the volume V2 of the second flask (Vi > V) The flasks are connected by a narrow glass tube which has a drop of liquid mercury. Because the pressure in each flask is the same the drop of mercury is at equilibrium exactly in the middle of the glass tube. Would the drop of mercury move to either side if both flasks were heated up to the same higher temperature Thigh? The volume of the glass tube is negligibly small in comparison to the volume of flasks. Therefore, the change of the position for the mercury drop simply serves as an indicator of the pressure change between flask #1 and 2. For example, if the mercury drop moves from the center to the flask #2 it means that pressure in flask #1 > pressure in flask #2. Circle the correct answer below and support it with your calculations. Glass tube with a mercury drop #2 #1 Answer: The drop of mercury will: a) move to flask #1 ; b) move to flask #2; c) stay at the center;
Chemistry: An Atoms First Approach
2nd Edition
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Steven S. Zumdahl, Susan A. Zumdahl
Chapter8: Gases
Section: Chapter Questions
Problem 94E: Xenon and fluorine will react to form binary compounds when a mixture of these two gases is heated...
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Transcribed Image Text:Two flasks have the same gas at the same initial temperature T and pressure P. The volume V
of the flask #1 is much bigger than the volume V2 of the second flask (Vi > V) The flasks are
connected by a narrow glass tube which has a drop of liquid mercury. Because the pressure in
each flask is the same the drop of mercury is at equilibrium exactly in the middle of the glass
tube. Would the drop of mercury move to either side if both flasks were heated up to the same
higher temperature Thigh? The volume of the glass tube is negligibly small in comparison to the
volume of flasks. Therefore, the change of the position for the mercury drop simply serves as
an indicator of the pressure change between flask #1 and 2. For example, if the mercury drop
moves from the center to the flask #2 it means that pressure in flask #1 > pressure in flask #2.
Circle the correct answer below and support it with your calculations.
Glass tube with a mercury drop
#2
#1
Answer: The drop of mercury will:
a) move to flask #1 ;
b) move to flask #2;
c) stay at the center;
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