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Two flasks have the same gas at the same initial temperature T and pressure P. The volume Vof the flask #1 is much bigger than the volume V2 of the second flask (Vi > V) The flasks areconnected by a narrow glass tube which has a drop of liquid mercury. Because the pressure ineach flask is the same the drop of mercury is at equilibrium exactly in the middle of the glasstube. Would the drop of mercury move to either side if both flasks were heated up to the samehigher temperature Thigh? The volume of the glass tube is negligibly small in comparison to thevolume of flasks. Therefore, the change of the position for the mercury drop simply serves asan indicator of the pressure change between flask #1 and 2. For example, if the mercury dropmoves from the center to the flask #2 it means that pressure in flask #1 > pressure in flask #2.Circle the correct answer below and support it with your calculations.Glass tube with a mercury drop#2#1Answer: The drop of mercury will:a) move to flask #1 ;b) move to flask #2;c) stay at the center;

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Can you please help me solve this problem and explain how you got the answers?

Two flasks have the same gas at the same initial temperature T and pressure P. The volume V
of the flask #1 is much bigger than the volume V2 of the second flask (Vi > V) The flasks are
connected by a narrow glass tube which has a drop of liquid mercury. Because the pressure in
each flask is the same the drop of mercury is at equilibrium exactly in the middle of the glass
tube. Would the drop of mercury move to either side if both flasks were heated up to the same
higher temperature Thigh? The volume of the glass tube is negligibly small in comparison to the
volume of flasks. Therefore, the change of the position for the mercury drop simply serves as
an indicator of the pressure change between flask #1 and 2. For example, if the mercury drop
moves from the center to the flask #2 it means that pressure in flask #1 > pressure in flask #2.
Circle the correct answer below and support it with your calculations.
Glass tube with a mercury drop
#2
#1
Answer: The drop of mercury will:
a) move to flask #1 ;
b) move to flask #2;
c) stay at the center;
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Two flasks have the same gas at the same initial temperature T and pressure P. The volume V of the flask #1 is much bigger than the volume V2 of the second flask (Vi > V) The flasks are connected by a narrow glass tube which has a drop of liquid mercury. Because the pressure in each flask is the same the drop of mercury is at equilibrium exactly in the middle of the glass tube. Would the drop of mercury move to either side if both flasks were heated up to the same higher temperature Thigh? The volume of the glass tube is negligibly small in comparison to the volume of flasks. Therefore, the change of the position for the mercury drop simply serves as an indicator of the pressure change between flask #1 and 2. For example, if the mercury drop moves from the center to the flask #2 it means that pressure in flask #1 > pressure in flask #2. Circle the correct answer below and support it with your calculations. Glass tube with a mercury drop #2 #1 Answer: The drop of mercury will: a) move to flask #1 ; b) move to flask #2; c) stay at the center;

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check_circleAnswer
Step 1

In the given problem, the gas is same. The gases are being heated up to the same final temperature. So, all the conditions for the gas are same except for the pressure and volume. So, this is an application of Boyle's law.

Step 2

According to the Boyle's law, under constant conditions of temperature, for the same amount of a gas, the pressure and volume of the gas are inversely proportional to each other.

Mathematically, 

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Step 3

Since, volume V1 > V2

Thus, pressure P1 < P2

Thus, the merc...

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