Two moles of gas initially at a pressure of 2.00 atm and a volume of 0.300 L has internal energy equal to 91.0 J. In its final state, the gas is at a pressure of 1.50 atm and a volume of 0.800 L, and its internal energy equals 182 J. P (atm) 2.00 B 1.50 F V (liters) 0,300 0,800 (a) For the paths IAF, IBF, and IF in the figure above, calculate the work done on the gas. WJAF=-76 WRE= IBF Your response differs from the correct answer by more than 10%. Double check your calculations. J "IF The response you submitted has the wrong sign. J (b) For the paths IAF, IBF, and IF in the figure above, calculate the net energy transferred to the gas by heat in the process. QIAF= 167 QIBF= QIf =

Physics for Scientists and Engineers: Foundations and Connections
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Author:Katz, Debora M.
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Chapter21: Heat And The First Law Of Thermodynamics
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Two moles of gas initially at a pressure of 2.00 atm and a volume of 0.300 L has internal energy equal to 91.0 J. In its final state, the gas is at a pressure of 1.50 atm and a
volume of 0.800 L, and its internal energy equals 182 J.
P (atm)
2.00
В
1.50
F
V (liters)
0.300
0.800
(a) For the paths IAF, IBF, and IF in the figure above, calculate the work done on the gas.
W
IAF
=|-76
IBF
Your response differs from the correct answer by more than 10%. Double check your calculations. J
W
IF
The response you submitted has the wrong sign. J
(b) For the paths IAF, IBF, and IF in the figure above, calculate the net energy transferred to the gas by heat in the process.
QIAF= 167
QIBF=
Qif=
!!
Transcribed Image Text:Two moles of gas initially at a pressure of 2.00 atm and a volume of 0.300 L has internal energy equal to 91.0 J. In its final state, the gas is at a pressure of 1.50 atm and a volume of 0.800 L, and its internal energy equals 182 J. P (atm) 2.00 В 1.50 F V (liters) 0.300 0.800 (a) For the paths IAF, IBF, and IF in the figure above, calculate the work done on the gas. W IAF =|-76 IBF Your response differs from the correct answer by more than 10%. Double check your calculations. J W IF The response you submitted has the wrong sign. J (b) For the paths IAF, IBF, and IF in the figure above, calculate the net energy transferred to the gas by heat in the process. QIAF= 167 QIBF= Qif= !!
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