Two moles of gas initially at a pressure of 2.00 atm and a volume of 0.300 L has internal energy equal to 91.0 J. In its final state, the gas is at a pressure of 1.50 atm and a volume of 0.800 L, and its internal energy equals 182 J.For the paths IAF, IBF, and IF in the figure above, calculate the work done on the gas.a. W(IAF)b. W(IF)c. Q(IAF)d. Q(IBF)e. (QIF)

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Asked Nov 18, 2019
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Two moles of gas initially at a pressure of 2.00 atm and a volume of 0.300 L has internal energy equal to 91.0 J. In its final state, the gas is at a pressure of 1.50 atm and a volume of 0.800 L, and its internal energy equals 182 J.

For the paths IAFIBF, and IF in the figure above, calculate the work done on the gas.

a. W(IAF)

b. W(IF)

c. Q(IAF)

d. Q(IBF)

e. (QIF) 

 

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Conversion
1atm
013 x10 Pa
Latm.L2 atm) 11)
LO1SK10
Latm
to1.3 J
1atm
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Conversion 1atm 013 x10 Pa Latm.L2 atm) 11) LO1SK10 Latm to1.3 J 1atm

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Step 3
Giren
bessure, PPa = 2.00 atm
Pressure, PA
PF =
|.50 atm
Volume, VA
Volume, Ve = VE =
= 0. 300 L
O.800 L
91.0 J
Internal ene
Internal energy F =
182 J
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Giren bessure, PPa = 2.00 atm Pressure, PA PF = |.50 atm Volume, VA Volume, Ve = VE = = 0. 300 L O.800 L 91.0 J Internal ene Internal energy F = 182 J

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