Two point charges, Q1 = -35 µC and Q2 = 44 µC, are separated by a distance of 12 cm. The electric field at the point P is zero (Eigure 1). Figure 1 of 1> Q2 12 cm
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please answer both. I don't need explanations
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- Sketch the electric field lines in the vicinity of two opposite charges, where the negative charge is three times greater in magnitude than the positive. (See Figure 1S.47 for a similar situation).Determine if approximate cylindrical symmetry holds for the following situations. State why or why not. (a) A 300-cm long copper rod of radius 1 cm is charged with +500 nC of charge and we seek electric field at a point 5 cm from the center of the rod. (b) A 10-cm long copper of radius 1 cm is charged with +500 nC of charge and we seek electric field at a point 5 cm from the center of the rod. (c) A 150-cm wooden rod is glued to a 150-cm plastic rod to make a 300 cm long rod, which is then painted with a charged paint so that one obtains a uniform charge density. The radius of each rod is 1 cm, and we seek an electric field at a point that is 4 cm from the center of the rod. (d) Same rod as (c), but we seek electric field at a point that is 500 cm from the center of the rod.(a) Find the magnitude and direction of the electric field at the position of the 2.00 C charge in Figure P13.13. (b) How would the electric field at that point be affected if the charge there were doubled? Would the magnitude of the electric force be affected?
- A long cylinder of copper of radius 3 cm is charged so that it has a uniform charge per unit length on its surface of 3 C/m. (a) Find the electric field inside and outside the cylinder. (b) Draw electric field lines in a plane perpendicular to the rod.Give an expression for the electric field strength ?E at a point in terms of the charge ?q and distance ?r from the charge to that point. Use ?k for 14??014πε0 (i.e. ?≡14??0k≡14πε0). Use the following notation (without the quotes): "/" for division, "*" for multiplication, "+" an "-" as usual. For powers used "^2", while for square root use "sqrt". To indicate that square root applies to the whole expression use brackets - for example, for ??‾‾‾‾√AB use sqrt(A*B). For Greek letters such as ?π, ?α etc. use pi, alpha. For example to get 1??2???‾‾‾‾√1πA2BAB use 1/pi*A^2/B*sqrt(AB). Please use the exact variables given in the conditions of the problem: e.g if ?L is given, then do not use ?l.question 5: The point charges are located at 1, 5, 8, and 14 cm along the x-axis as represented in the Figure. Take q = 5.2 nC. Find the x-component of the total electric field, in newtons per coulomb, at x = 11 cm in N/C. E(x = 11 cm) = ???
- Imagine you have four identical charge q, placed on the corners of a square. If q = 4.69 nC, then the side of the square is s = 9.65 cm, calculate the magnitude of the electric field acting on the charge at the upper right corner. NOTE: Final answer in SIX decimal places. Then, state the SI unit of the variable being sought off.Consider the diagram of the two charges shown below. The charge qA=-5.70 x 10-8 C while the distance x=0.260 m and the distance y=2.80 m. If the electric field due to the charges at point P is equal to zero, what is the charge qB? If the charge is negative include the negative sign. If the charge is positive do NOT include the sign of the charge Express your answer in Coulombs x 10-8 to two decimal places but do not include units in your answer. For example, if your answer was 2.31x 10-8 C you would input 2.31 in the box below.Pls help me with the following and explain. make sure its correct, thanks A point charge -5 q� is held fixed at the origin, and a second charge +q� is held fixed at x� = 8.0 mm. Where is the net electric field of these two charges zero? Express your answer with appropriate units.
- Two rods A and B of lengths L and L/2, respectively, are arranged as shown in the diagram below where d = L/2. Here, L = 2.40 m and the charge on rod A is 30.5 µC. If the net electric field at the midpoint between the two rods is zero, what is the charge (magnitude and sign) on rod B? The field at a distance y on the perpendicular bisector of a rod of length L is given by Erod = 2kq/y(L2 + 4y2) 1/2. <-- y times the square root of (L 2 + 4y2 ).Express answer/s in mks (SI) . Draw diagram whenever necessary Three charges are placed on three corners of a square, as shown in the figure. Each side of the square is24.0 cm. Compute the magnitude and direction of the electric field at the fourth corner.One of my homework problems asks this: A non-conducting sphere of radius R = 9.0 cm carries a charge Q = 5.0 mC distributed uniformly throughout its volume. At what distance, measured from the center of the sphere, does the electric field reach a value equal to half its maximum value? The correct answer is marked as 4.5 cm and 12.7 cm. I worked out: Emax = kQ/R2 for half the max electric field, i'll use R2 for radius we need to find Ehalf = kQ/2R2 = kQ/R22 giving me: R2 = square root of 2R2 = R*square root of 2 = 9*square root of 2 = 12.7 cm I am unable to figure out how 4.5 cm is also the answer.