Two solid bars support a load P as shown. Bar (1) has a cross-sectional area of A1 = 4250 mm2 and an allowable normal stress of 95 MPa. Bar (2) has a cross-sectional area of A2 = 2750 mm2 and an allowable normal stress of 140 MPa. Assume x1 = 2.1 m, x2 = 3.6 m, y1 = 0.8 m, and y2 = 2.8 m. Determine the maximum load Pmax that can be supported by the structure without exceeding either allowable normal stress.

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter2: Axially Loaded Members
Section: Chapter Questions
Problem 2.3.2P: A long, rectangular copper bar under a tensile load P hangs from a pin that is supported by two...
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Two solid bars support a load P as shown. Bar (1) has a cross-sectional area of A1 = 4250 mm2 and an allowable normal stress of 95 MPa. Bar (2) has a cross-sectional area of A2 = 2750 mm2 and an allowable normal stress of 140 MPa. Assume x1 = 2.1 m, x2 = 3.6 m, y1 = 0.8 m, and y2 = 2.8 m. Determine the maximum load Pmax that can be supported by the structure without exceeding either allowable normal stress.

Two solid bars support a load Pas shown. Bar (1) has a cross-sectional area of A1 = 4250 mm2 and an allowable normal stress of 95
MPa. Bar (2) has a cross-sectional area of A2 = 2750 mm² and an allowable normal stress of 140 MPa. Assume x1 = 2.1 m, x2 = 3.6 m, y1
= 0.8 m, and y2 = 2.8 m. Determine the maximum load Pmax that can be supported by the structure without exceeding either allowable
normal stress.
C
A
(1)
B
V P
Answer: Pmax = i
kN
Transcribed Image Text:Two solid bars support a load Pas shown. Bar (1) has a cross-sectional area of A1 = 4250 mm2 and an allowable normal stress of 95 MPa. Bar (2) has a cross-sectional area of A2 = 2750 mm² and an allowable normal stress of 140 MPa. Assume x1 = 2.1 m, x2 = 3.6 m, y1 = 0.8 m, and y2 = 2.8 m. Determine the maximum load Pmax that can be supported by the structure without exceeding either allowable normal stress. C A (1) B V P Answer: Pmax = i kN
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