u = [[4,[5,5,3,1],[3,4,4],1],4,[[4,[5,1,1,2],5,[2,1,3]],[2,1,3],4],[5,[4,1,3]],4,4] print(u[2[1][0] + u[3][0] + u[4] + u[0][3] + u[5])
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- You are given a list of randomly arranged numbers, for example (11,7,18,5,17,13). The triple (11,7, 5) is called the "inversion triple" because (5<7<11) in terms of value, while the index of 5 in the list is greater than the index of 7, and the index of 7 is greater than 11. Therefore, we can find 2 inversions in such list as follows: (11,7,5), and (18,17,13). Your main task is to find the total number of inversions in any given list. a) Design a brute-force algorithm to return the number of possible inversions, and analyse the complexity of your solution b) Develop a python code to implement your brute-force algorithm. [The marks depend on the correctness of the code, indentation, comments, test-case] c) Design a more efficient algorithm to do the same task with less complexity, and analyse the complexity of your solution. [Important instruction to be followed: Create an arbitrary unsorted list of 8 characters and use it to provide full explanation of how your proposed…Write a program in java that randomly fills in 0s and 1s into an n-by-n matrix, prints the matrix, and finds the rows and columns with the most 1s. (Hint: Use two ArrayLists to store the row and column indices with the most 1s.)JAVA:Use the "natural split" algorithm on the file split.txt and answer the following question: How many elements are in the first list? (Split into two files.) Splt.txt 200494 774 644 345 521 61 27 28 584 569 66 857 210 2 211 675 548 596 188 647 671 517 408 475 615 113 731 522 850 17 640 940 556 517 602 935 76 578 880 428 168 394 381 497 247 368 137 138 619 973 895 106 838 45 921 800 681 660 490 427 937 917 786 959 152 604 837 749 684 963 926 963 988 492 385 458 788 7 62 46 932 996 787 634 34 616 71 128 686 578 923 532 933 545 100 224 895 595 342 933 934 797 120 565 495 884 237 648 843 599 157 843 192 279 301 649 382 881 667 178 126 746 44 601 22 52 769 708 991 83 447 786 525 168 328 922 153 367 22 689 834 774 93 110 547 597 644 726 237 20 370 573 391 225 750 897 956 839 951 455 8 509 746 338 576 276 277 341 274 891 723 53 966 271 50 990 493 823 833 306 619 461 768 832 736 759 920 451 549 833 911 123 907 225 252 179 177 272 747 859
- JAVA: Use the "natural split" algorithm on the file split.txt and answer the following question: How many elements are in the first list? Split.txt file 200494 774 644 345 521 61 27 28 584 569 66 857 210 2 211 675 548 596 188 647 671 517 408 475 615 113 731 522 850 17 640 940 556 517 602 935 76 578 880 428 168 394 381 497 247 368 137 138 619 973 895 106 838 45 921 800 681 660 490 427 937 917 786 959 152 604 837 749 684 963 926 963 988 492 385 458 788 7 62 46 932 996 787 634 34 616 71 128 686 578 923 532 933 545 100 224 895 595 342 933 934 797 120 565 495 884 237 648 843 599 157 843 192 279 301 649 382 881 667 178 126 746 44 601 22 52 769 708 991 83 447 786 525 168 328 922 153 367 22 689 834 774 93 110 547 597 644 726 237 20 370 573 391 225 750 897 956 839 951 455 8 509 746 338 576 276 277 341 274 891 723 53 966 271 50 990 493 823 833 306 619 461 768 832 736 759 920 451 549 833 911 123 907 225 252 179 177 272 747 859Write a Java program to find continuous sub array of the given array whose sum is equal to a given number. For example, If {12, 5, 31, 9, 21, 8} is the given array and 45 is the given number, then you have to find continuous sub array in this array such that whose elements add up to 45. In this case, {5, 31, 9} is such sub array whose elements add up to 45.Write a Java code # Resistor ColorResistors have color coded bands, where each color maps to a number. The first 2 bands of a resistor have a simple encoding scheme: each color maps to a single number.These colors are encoded as follows:- Black: 0- Brown: 1- Red: 2- Orange: 3- Yellow: 4- Green: 5- Blue: 6- Violet: 7- Grey: 8- White: 9Mnemonics map the colors to the numbers, that, when stored as an array, happen to map to their index in thearray: Better Be Right Or Your Great Big Values Go Wrong.More information on the color encoding of resistors can be found in the [Electronic color code Wikipedia article]# Running the testsYou can run all the tests for an exercise by entering $ gradle test in your terminal.## SourceMaud de Vries, Erik Schierboom [https://github.com/exercism/problem-specifications/issues/1458] Consider the structure that the code must have; it is given in the picture
- For this problem I have a java code: import java.util.Arrays; import java.util.Scanner; public class MergeSortWeightedSumInversion { public static long merge(int arr[], int l, int mid, int r) { long weight = 0; int n1 = mid-l+1; int n2 = r-mid; int[] a = new int[n1]; int[] b = new int[n2]; for(int i = 0; i < n1; i++) { a[i] = arr[l+i]; } for(int i = 0; i < n2; i++) { b[i] = arr[mid+i+1]; } int i = 0, j = 0, k = l; while(i<n1 && j<n2) { if(a[i] <= b[j]) { arr[k] = a[i]; k++; i++; } else { weight += (a[i] + b[j]); arr[k] = b[j]; k++; j++; } } while(i<n1) { arr[k] = a[i]; k++; i++; } while(j<n2) { arr[k] = b[j]; k++; j++; } return weight; } public static long mergeSort(int arr[], int l, int r) { long weight = 0; if(l < r) { int mid = (l+r)/2; weight += mergeSort(arr, l, mid); weight += mergeSort(arr,mid+1,r); weight += merge(arr,l,mid,r); } return weight; } public static void main(String[] args) { Scanner scan = new Scanner(System.in); int n; n =…implement a parametrized version of mergesort that will allow us to choose how many parts the input array will be divided into.This method will take an integer array and integer K as inputs and produce one integer array as output. It will sort the input array by dividing it into K parts, recursively sorting those parts, and using the mergeAll method to merge the K sorted arrays into one sorted array. Implement the mergesortK method public static int[] mergesortK(int[] arr, int k) { return new int[] {-1}; } *must be done in this format and in java pleasein Python Minima in permutations. Write a program that takes an integer n from the command line, generates a random permutation, prints the permutation, and prints the number of left-to-right minima in the permutation (the number of times an element is the smallest seen so far). Then write a program that takes integers m and n from the command line, generates m random permutations of length n, and prints the average number of left-to-right minima in the permutations generated
- Create a test program to test this MergeSort Program: package ArraySplit; import java.util.Arrays; public class ArraySplit { public static void mergeSort(int[] a, int n) { if (n < 2) { return; } int mid = n / 2; int[] l = new int[mid]; int[] r = new int[n - mid]; for (int i = 0; i < mid; i++) { l[i] = a[i]; } for (int i = mid; i < n; i++) { r[i - mid] = a[i]; } mergeSort(l, mid); mergeSort(r, n - mid); merge(a, l, r, mid, n - mid); } public static void merge(int[] a, int[] l, int[] r, int left, int right) { int i = 0, j = 0, k = 0; while (i < left && j < right) { if (l[i] <= r[j]) { a[k++] = l[i++]; } else { a[k++] = r[j++]; } } while (i < left) { a[k++] = l[i++]; } while (j < right) { a[k++] = r[j++]; } } }Write an application in java language using a hash table that finds all the pairs of two integers within the below array that add up to 12. Array = {4,9,6,13,5,3,2,8}Java program to Draw the hash table that results from adding the f to a hash table using shift folding of the first two digits with the last two digits. Use a table size of 13.