Use the Born-Haber cycle to calcuate the standard enthalpy of formation for LiCls) given the following data: Enthalpy of sublimation for Li: 155.2 kJ/mol First ionization energy for Li: 520. kJ/mol Bond dissociation energy for Cl2: 242.7 kJ/mol First electron affinity for CI: 349 kJ/mol Lattice energy for LiCl: - 828 kJ/mol

Use the Born-Haber cycle to calcuate the standard enthalpy of formation for LiCls) given the following data: Enthalpy of sublimation for Li: 155.2 kJ/mol First ionization energy for Li: 520. kJ/mol Bond dissociation energy for Cl2: 242.7 kJ/mol First electron affinity for CI: 349 kJ/mol Lattice energy for LiCl: - 828 kJ/mol

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter6: Covalent Bonding

Section: Chapter Questions

Problem 110QRT

See similar textbooks

Similar questions

The lattice energy of KF is 794 kJ/mol, and the interionic distance is 269 pm. The Na—F distance in NaF, which has the same structure as KF, is 231 pm. Which of the following values is the closest approximation of the lattice energy of NaF: 682 kJ/mol, 794 kJ/mol, 924 kJ/mol, 1588 kJ/mol, or 3175 kJ/mol? Explain your answer.
Use the Born Haber cycle (show relevant steps) to determine the lattice energy of CsCl (s) from the following data: ΔHf°[CsCl(s)] = -442.8 kJ/mol; enthalpy of sublimation of Cesium is 78.2 kJ/mol; enthalpy of dissociation of Cl2 (g) = 243 kJ/mol Cl2 ; IE1 for Cs(g) = 375.7 kJ/mol; electron affinityenthalpy-EA1 for Cl(g) = -349kJ/mol.
How can I use the Born Haber cycle to establish the lattice energy of CsCl (s)from the following data: ΔHf° [CsCl(s)] = -442.8 kJ/mol; enthalpy of sublimation of Cesium is 78.2 kJ/mol; enthalpy of dissociation of Cl2 (g) = 243 kJ/mol Cl2 ; IE1 for Cs(g) = 375.7 kJ/mol; electron affinity enthalpy-EA1 for Cl(g) = -349kJ/mol.
Calculate the lattice energy for LiBr(s) given the following: sublimation energy for Li(s) +166 kJ/mol ΔHf for Br(g) +97 kJ/mol first ionization energy of Li(g) +520. kJ/mol electron affinity of Br(g) –325 kJ/mol enthalpy of formation of LiBr(s) –351 kJ/mol
Using the following data, calculate the lattice energy of calcium chloride: Ca2+(g) + 2Cl– (g) → CaCl2(s) ΔHlattice = ? Sublimation enthalpy of calcium ΔH = 177.8 kJ/mol First ionization energy of calcium ΔH = 590.2 kJ/mol Second ionization energy of calcium ΔH = 1144.2 kJ/mol First electron affinity of chlorine ΔH = –349 kJ/mol Heat of formation of CaCl2(s) ΔH = –795.4 kJ/mol Bond energy of Cl2 (see Table 2) Use Hess’s law to calculate the lattice energy of calcium chloride. set-up must show all the chemical equations and you must show how their H values add up to give your answer.
You are given the following Born-Haber cycle information. Based on the values listed, determine the lattice energy for MgO. Enthalpy of formation for magnesium oxide: -602 kJ/mol Enthalpy of sublimation for magnesium: 150 kJ/mol First ionization energy for magnesium: 738 kJ/mol Second ionization energy for magnesium: 1451 kJ/mol Bond dissociation energy for molecular oxygen: 498 kJ/mol First electron affinity for oxygen: -141 kJ/mol Second electron affinity for oxygen: 878 kJ/mol
Use the Born–Haber cycle to calculate the enthalpy of formationof KBr, which crystallizes in the NaCl lattice. Use thesedata in the calculation: Hvap(Br2) = 29.8 kJ/mol; Br2 bondenergy = 190.2 kJ/mol; and Hsub(K) = 79 kJ/mol.
This thermodynamic cycle describes the formation of an ionic compound MX2 from a metal element M and nonmetal element X in their standard states. Based of the table (picture): A. What is the lattice enthalpy of MX2 ? (in kJ/mol) B. What is the enthalpy of formation of MX2 ? (in kJ/mol) C. Suppose both the electron affinity of X and the heat of sublimation of M were smaller. Would MX2 be more or less stable?
1. Below is a list of enthalpy changes for the Born-Haber cycle for the formation of solid LiF from Li(s) and F(g). Use these data to determine the lattice energy for the formation LiF(s). Li(s) → Li(g) ΔH1 = +162 kJ/mol Li(g) → Li+(g) + e- ΔH2 = +520.2 kJ/molF2(g) → 2F(g) ΔH3 = 154 kJ/mol F(g) + e- → F-(g) ΔH4 = -328 kJ/molLi(s) + 1/2F2(g) → LiF(s) ΔHf = -612 kJ/mol Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a. 1371 kJ/mol b. -1371 kJ/mol c. 1043 kJ/mol d. -1043 kJ/mol
Given the following information, use the Kapustinskii equation (shown below and included in the additional information sheet I encouraged you to download and have available) to calculate the lattice energy for Cr2S3 in kJ/mol. Ionic radii: Cr3+ (62 pm), S2− (184 pm) d* = 34.5 pm Κ = 1.21 × 105 kJ pm/mol
Given the tabulated data, what is the lattice energy of crystalline calcium chloride?heat of sublimation for calcium +178 kJ/molfirst ionization energy for calcium +590 kJ/molsecond ionization energy for calcium +1145 kJ/molheat of dissociation for chlorine +122 kJ/mol(Cl2)electron affinity for chlorine -349 kJ/molheat of formation for calcium chloride -796 kJ/mol
Write the steps (reactions) for the Born-Haber cycle for MgCl2(s). Use the Born-Haber cycle to calculate the lattice energy of MgCl2(s). Some useful data to work with: For Mg: ΔΔHsub = 147 kJ/mol, IE1 and IE2 are 738 kJ/mol and 1450 kJ/mol, respectively. For chlorine: Bond energy = 243 kJ/mol, EA1 = -349 kJ/mol, respectively. The enthalpy of formation of magnesium chloride is -748.8 kJ/mol.