Use the drawing for Theorem 61 for exer- cises 4 to 7. Express answers as radicals and fractions if applicable. V4.If AD = 9 in., DB = 4 in., find DC, AC, and BC. %3D %3D 4.10 Proportional Segments in Right Triangles Theorem 61 It in a right triangle the perpendicular is drawn from the vertex of the right angle to the hypotenuse: 1. The two triangles thus formed are similar to the given tri- angle and to each other. II. The perpendicular is the mean proportional between the segments of the hypotenuse. II. Each leg of the given triangle is the mean proportional between the hypotenuse and the adjacent segment of the hypotenuse. Given: Right AABC, and CD the I from C to the hypotenuse AB Prove: I. AACD ~ AABC ~ ACBD II. AD : CD = CD : DB – AD = CD Bb BC BA %3D B. AC DB ep вс III. AD : AC = AC : AB and BD : BC = BC : BA ло %3D AB %3D

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.2: Trigonometric Functions Of Angles
Problem 50E
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Use the drawing for Theorem 61 for exercise 4. Express answers as radicals and fractions if applicable.

Use the drawing for Theorem 61 for exer-
cises 4 to 7. Express answers as radicals
and fractions if applicable.
V4.If AD = 9 in., DB = 4 in., find DC, AC,
and BC.
%3D
%3D
Transcribed Image Text:Use the drawing for Theorem 61 for exer- cises 4 to 7. Express answers as radicals and fractions if applicable. V4.If AD = 9 in., DB = 4 in., find DC, AC, and BC. %3D %3D
4.10 Proportional Segments in Right Triangles
Theorem 61
It in a right triangle the perpendicular is drawn from the vertex of
the right angle to the hypotenuse:
1. The two triangles thus formed are similar to the given tri-
angle and to each other.
II. The perpendicular is the mean proportional between the
segments of the hypotenuse.
II. Each leg of the given triangle is the mean proportional
between the hypotenuse and the adjacent segment of the
hypotenuse.
Given: Right AABC, and CD the I from C to the
hypotenuse AB
Prove: I. AACD ~ AABC ~ ACBD
II. AD : CD = CD : DB –
AD = CD
Bb BC
BA
%3D
B.
AC
DB
ep
вс
III. AD : AC = AC : AB and BD : BC = BC : BA
ло
%3D
AB
%3D
Transcribed Image Text:4.10 Proportional Segments in Right Triangles Theorem 61 It in a right triangle the perpendicular is drawn from the vertex of the right angle to the hypotenuse: 1. The two triangles thus formed are similar to the given tri- angle and to each other. II. The perpendicular is the mean proportional between the segments of the hypotenuse. II. Each leg of the given triangle is the mean proportional between the hypotenuse and the adjacent segment of the hypotenuse. Given: Right AABC, and CD the I from C to the hypotenuse AB Prove: I. AACD ~ AABC ~ ACBD II. AD : CD = CD : DB – AD = CD Bb BC BA %3D B. AC DB ep вс III. AD : AC = AC : AB and BD : BC = BC : BA ло %3D AB %3D
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