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Use the equation below to determine the limiting reactant. Mg (s) + 2 HC1 (aq) → MgCl, (aq) + H2 (g) When 6 moles of Mg is reacted with 6 moles of HCl, what is the limiting reactant?

Use the equation below to determine the limiting reactant. Mg (s) + 2 HC1 (aq) → MgCl, (aq) + H2 (g) When 6 moles of Mg is reacted with 6 moles of HCl, what is the limiting reactant?

General, Organic, and Biological Chemistry
General, Organic, and Biological Chemistry
7th Edition
ISBN:9781285853918
Author:H. Stephen Stoker
Publisher:H. Stephen Stoker
Chapter6: Chemical Calculations: Formula Masses, Moles, And Chemical Equations
Section: Chapter Questions
Problem 6.66EP: For the chemical reaction C3H8O2+4O23CO2+4H2O how many product molecules are formed when nine C3H8O2...
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Use the equation below to determine the limiting reactant. Mg (s) + 2 HC1 (aq) → MgCl, (aq) + H2 (g) When 6 moles of Mg is reacted with 6 moles of HCl, what is the limiting reactant?
Transcribed Image Text:Use the equation below to determine the limiting reactant. Mg (s) + 2 HC1 (aq) → MgCl, (aq) + H2 (g) When 6 moles of Mg is reacted with 6 moles of HCl, what is the limiting reactant?
Mg because you will have 0 moles of Mg and 3 moles of HCl left over HCl because you will have 3 moles of HCl left over and 0 moles Mg HCl because you will have 0 moles of HCl and 3 moles of Mg left over Mg because you will have 3 moles of Mg and 0 moles HCi
Transcribed Image Text:Mg because you will have 0 moles of Mg and 3 moles of HCl left over HCl because you will have 3 moles of HCl left over and 0 moles Mg HCl because you will have 0 moles of HCl and 3 moles of Mg left over Mg because you will have 3 moles of Mg and 0 moles HCi
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