An Equilibrium System N₂(g) + C₂H₂(g) = 2 HCN(g) N₂(g) and C₂H₂(g) are injected into a closed 1.00 L flask and the system is allowed to reach equilibrium. The concentrations at equilibrium are recorded in the following data table. Numerical Response Gas N₂(g) C₂H₂(g) HCN(g) Equilibrium Concentration (mol/L) 0.488 0.513 0.0240 15. The value of K for the equilibrium system above, expressed in scientific notation, is a.bc x 10-d. The values of a, b, c, and d are. and b c a ." d (Record all four digits of your answer in the numerical-response section on the answer sheet.)

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Chapter17: Equilibrium
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Problem 24A
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Use the following information to answer numerical-response question 15.
An Equilibrium System
N₂(g) + C₂H₂(g) = 2 HCN(g)
N₂(g) and C₂H₂(g) are injected into a closed 1.00 L flask and the system is allowed to reach
equilibrium. The concentrations at equilibrium are recorded in the following data table.
Gas
N₂(g)
C₂H₂(g)
HCN(g)
Equilibrium
Concentration (mol/L)
0.488
0.513
0.0240
Numerical Responsent
15. The value of K, for the equilibrium system above, expressed in scientific notation, is
a.bc x 10-d. The values of a, b, c, and d are
and
a
b
с
d
(Record all four digits of your answer in the numerical-response section on the answer sheet.)
bloow onesna
Transcribed Image Text:Use the following information to answer numerical-response question 15. An Equilibrium System N₂(g) + C₂H₂(g) = 2 HCN(g) N₂(g) and C₂H₂(g) are injected into a closed 1.00 L flask and the system is allowed to reach equilibrium. The concentrations at equilibrium are recorded in the following data table. Gas N₂(g) C₂H₂(g) HCN(g) Equilibrium Concentration (mol/L) 0.488 0.513 0.0240 Numerical Responsent 15. The value of K, for the equilibrium system above, expressed in scientific notation, is a.bc x 10-d. The values of a, b, c, and d are and a b с d (Record all four digits of your answer in the numerical-response section on the answer sheet.) bloow onesna
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