Use the Image to solve these problems. 1. What is the order of this reaction with respect to NO2?2. Write a rate law for this reaction, and calculate the value of the rate constant (k). (Report in scientific notation to 3 sig figs without units)Rate law:Rate constant (k):3. Determine the half-life for this reaction. (Report in scientific notation to 3 sig figs without units)4. Calculate [NO2] at 2.70 x 104 seconds after the start of the reaction. (Report to 3 sig figs without units) The rate of the reaction NO₂ + CO → NO + CO₂ dependsonly on the concentration of nitrogen dioxide below 225 ° Ata temperature below 225 °C, the following data werecollected.[NO₂] (mol/L)time (s)00.5001.20 x 10³0.4443.00 x 10³0.3814.50 x 10³0.3409.00 x 10³0.2501.80 x 10²0.174Use Excel to graph this data and answer the next 4 questions.

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Answered: Use the Image to solve these problems.…

Chemistry for Engineering Students

4th Edition

ISBN:9781337398909

Author:Lawrence S. Brown, Tom Holme

Publisher:Lawrence S. Brown, Tom Holme

Chapter11: Chemical Kinetics

Section: Chapter Questions

Problem 11.36PAE: The reaction NO(g) + O,(g) — NO,(g) + 0(g) plays a role in the formation of nitrogen dioxide in...

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Use the Image to solve these problems.

1. What is the order of this reaction with respect to NO₂?

2. Write a rate law for this reaction, and calculate the value of the rate constant (k). (Report in scientific notation to 3 sig figs without units)

Rate law:

Rate constant (k):

3. Determine the half-life for this reaction. (Report in scientific notation to 3 sig figs without units)

4. Calculate [NO₂] at 2.70 x 10⁴ seconds after the start of the reaction. (Report to 3 sig figs without units)

The rate of the reaction NO₂ + CO → NO + CO₂ depends
only on the concentration of nitrogen dioxide below 225 ° At
a temperature below 225 °C, the following data were
collected.
[NO₂] (mol/L)
time (s)
0
0.500
1.20 x 10³
0.444
3.00 x 10³
0.381
4.50 x 10³
0.340
9.00 x 10³
0.250
1.80 x 10²
0.174
Use Excel to graph this data and answer the next 4 questions.

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