Use the Laplace transform to solve the following initial value problem: y' + 8y = 0 y(0) = 3, y(0) = -2 First, using Y for the Laplace transform of y(t), i.e., Y = L{y(t)}, find the equation you get by taking the Laplace transform of the differential equation = 0 Now solve for Y(s) and write the above answer in its partial fraction decomposition, Y(s) = + where a < b sta s+b Y(s) = Now by inverting the transform, find y(t) =

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