Use the References to access important values if needed for this question. The equilibrium constant, Ke, for the following reaction is 0.00650 at 298 K. 2NOBr(g)2NO(g) + Br₂ (9) If an equilibrium mixture of the three gases in a 17.8 L container at 298 K contains 0.378 mol of NOBr(g) and 0.461 mol of NO, the equilibrium concentration of Br2 Is M. Submit Answer Retry Entire Group 9 more group attempts remaining

Chemistry: An Atoms First Approach
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Chapter12: Chemical Equilibrium
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The equilibrium constant, Ke, for the following reaction is 0.00650 at 298 K.
2NOBr(g) 2NO(g) + Br₂ (g)
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If an equilibrium mixture of the three gases in a 17.8 L container at 298 K contains 0.378 mol of NOBr(g) and 0.461
mol of NO, the equilibrium concentration of Br₂ Is
M.
000
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F
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%
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Transcribed Image Text:The equilibrium constant, Ke, for the following reaction is 0.00650 at 298 K. 2NOBr(g) 2NO(g) + Br₂ (g) $ 4 Forms Office of t... KB Viewing Your Aca... Submit Answer If an equilibrium mixture of the three gases in a 17.8 L container at 298 K contains 0.378 mol of NOBr(g) and 0.461 mol of NO, the equilibrium concentration of Br₂ Is M. 000 000 F4 R F Show Hint % 5 Scholarship Ameri... [Review Topics] [References] Use the References to access important values if needed for this question. Retry Entire Group 9 more group attempts remaining T G Cengage Learning Cengage Technical Support ^ 6 Have Changes in... MacBook Air S Y H & 7 F7 U * 8 ►II F8 ( 9 K A F9 O -0 ) bio 1108 chat F10 SAVAGE X FENTY... Previous F11 +11 Next> Save and Exit F12 17
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