Use the Reterences to access important values ii needed for this question.A scientist measures the standard enthalpy change for the following reaction to be 8.0 kJFe(s) 2 HCl(aq)FeCl2 (s) H2(Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of HCl(aq) iskJ/molSubmit AnswerRetry Entire Group9 more group attempts remaining

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Asked Nov 15, 2019
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Use the Reterences to access important values ii needed for this question.
A scientist measures the standard enthalpy change for the following reaction to be 8.0 kJ
Fe(s) 2 HCl(aq)FeCl2 (s) H2(
Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of HCl(aq) is
kJ/mol
Submit Answer
Retry Entire Group
9 more group attempts remaining
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Use the Reterences to access important values ii needed for this question. A scientist measures the standard enthalpy change for the following reaction to be 8.0 kJ Fe(s) 2 HCl(aq)FeCl2 (s) H2( Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of HCl(aq) is kJ/mol Submit Answer Retry Entire Group 9 more group attempts remaining

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Expert Answer

Step 1

The standard enthalpy of formation of FeCl2 is -341.78 kJ/mol and that of Fe (s) and H2 (g) is 0. The standard enthalpy of the reaction is calculated as,

AHreaction AHproducts- AHreactants
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AHreaction AHproducts- AHreactants

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Step 2

Calculating the value of ΔHproducts

ДНроducts 3 ДН (FeCl) + дН (Н)
AHproducts= 1 x (-341.78) kJ+ 0
AHproducts 341.78 kJ
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ДНроducts 3 ДН (FeCl) + дН (Н) AHproducts= 1 x (-341.78) kJ+ 0 AHproducts 341.78 kJ

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Step 3

Calculating the value of &Delt...

ΔΗatants - ΔΗ (Fe) + ΔΗ (HCl)
ΔΗatants -0+2 ΔΗC
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ΔΗatants - ΔΗ (Fe) + ΔΗ (HCl) ΔΗatants -0+2 ΔΗC

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