Using Hess' Law and enthalpies of formation, find the ΔH°rxn for CH4 + 4Cl2  → CCl4 + HCl     Given ΔH°f  CH4 = -75 kJ/mol                    CCl4 = -96 kJ/mol                      HCl = -92 kJ/mol

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Chapter6: Thermochemistry
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Problem 129CWP: Which of the following substances have an enthalpy of formation equal to zero? a. Cl2(g) b. H2(g) c....
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Using Hess' Law and enthalpies of formation, find the ΔH°rxn for CH4 + 4Cl2  → CCl4 + HCl  

 

Given ΔH°f  CH4 = -75 kJ/mol

                   CCl4 = -96 kJ/mol

                     HCl = -92 kJ/mol

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