Using the data in the table, calculate AH° and AS° for the equilibrium shown below. Temp (K) % trans 492.6 522.0 555.0 580.0 613.0 2.69 3.61 5.09 6.42 8.23 Pd/C heat (Bu Bu (Bu 'Bu
Q: ΔG
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- If Sº in J/mol-K is 20 for H2SO4(aq), 20 for SO42-(aq), 141 for NaBr(aq), & 59 for Na+(aq), Sº for HBr(aq) must be about a. undetermined since it must be measured empirically b. 102 J/mol-K c. 79 J/mol-K d. 82 J/mol-KCompute for the PCl5 concentration in the following reaction at 78°C equilibrium. PCl3(g) + Cl2(g) ↔ PCl5(g) Kc = 3.572 x 104 PCl3 = 0.238 Cl2 = 0.168Consider the equilibrium system described by the chemical reaction below, which has a value of Kc equal to 1.87 × 10⁻³ at a certain temperature. If 5.00 g of solid PH₃BCl₃ and 0.0700 g of BCl₃ are added to a 4.500 L reaction vessel, what will the equilibrium concentration of PH₃ be? PH₃BCl₃(s) ⇌ PH₃(g) + BCl₃(g) 1.) Set up the expression for Qc and then evaluate it to determine the direction of the reaction. Do not combine or simplify terms 2.) Based on the given values and your value for Qc, set up ICE table in order to determine the unknown. 3.) Based on your ICE table, set up the expression foe Kc in order to determine the unknown. 4.) Based on your ICE table and expression for Kc, solve for the partial pressure of PH3, at equilibrium.
- Based on a Kc value of 0.170 and the data table given, what are the equilibrium conversations of XY, X, and Y, respectively?Determine the equilibrium constant (Kc): data is attached if neededConsider the equilibrium system described by the chemical reaction below, which has a value of Kc equal to 4.10 × 10⁻⁴ at a high temperature. If 0.20 mol N₂ and 0.15 mol O₂ react in a 1.0 L vessel, what will the equilibrium concentration of O₂ be? N₂(g) + O₂(g) ⇌ 2 NO(g) A )Set up the expression for Qc and then evaluate it to determine the direction of the reaction. Do not combine or simplify terms. Qc = _____/_____ = _____ Based on the given values and your value for Qc, set up ICE table in order to determine the unknown. Based on your ICE table, set up the expression for Kc in order to determine the unknown. Do not combine or simplify terms. Kc = (________) / (_______)= 4.10 × 10⁻⁴ Based on your ICE table and expression for Kc, solve for the concentration of O₂ at equilibrium. [O₂]eq = _____M
- Consider the equilibrium system described by the chemical reaction below, which has a value of Kc equal to 4.10 × 10⁻⁴ at a high temperature. If 0.20 mol N₂ and 0.15 mol O₂ react in a 1.0 L vessel, what will the equilibrium concentration of O₂ be? N₂(g) + O₂(g) ⇌ 2 NO(g) Set up the expression for Qc and then evaluate it to determine the direction of the reaction. Do not combine or simplify terms. Qc= (_______) / (_______) = (______) Based on the given values and your value for Qc, set up ICE table in order to determine the unknown. N₂(g) + O₂(g) ⇌ 2 NO(g) Initial (M) Change (M) Equilibrium (M) Based on your ICE table, set up the expression for Kc in order to determine the unknown. Do not combine or simplify terms. Kc = (________) / (_______)= 4.10 × 10⁻⁴ Based on your ICE table and expression for Kc, solve for the…What would be the equilibrium temperature if you drop 5.0 g of brass (Cp= 0.38 J/g-°C, initially at 68°C) and 3.5 g of aluminum (Cp = 0.9 J/g-°Cinitially at 83°C) into 105 g of water (Cp = 4.184 J/g-°C,initially at 23°C)?Dinitrogen tetroxide is 18.46 per cent dissociated at 25°C and 1.00 bar in the equilibrium N2O4(g) ⇌ 2NO2(g). Calculate K at (i) 25°C, (ii) 100°C given that ΔrH° = +56.2 kJ mol−1 over the temperature range.
- Compute for the PCl5 concentration in the given reaction at 78°C equilibrium. PCl3(g) + Cl2(g) ↔ PCl5(g) Kc = 3.572 x 104 PCl3 = 0.239 Cl2 = 0.169What would be the equilibrium temperature (oC) if you drop 5.0 g of brass (Cp = 0.38 J/g-oC, initially at 68oC) and 3.5 g of aluminum (Cp = 0.9 J/g-oC, initially at 83oC) into 20 g of water (Cp = 4.184 J/g-oC, initially at 23oC)?A 348.0 g block of Cu at 639.0°C is plunged into 1.47 kg of water (T = 27.4 °C) in an insulatedcontainer. What will be the final equilibrium T of the water and the Cu? (cCu = 0.385 J g-1°C1, cH2O = 4.184 J g-1°C-1)