Using the data table and rate law given below, what is the value of the rate constant, k. Rate = K[H₂O₂][1]m Trial 1 Trial 2 Trial 3 Vol. 0.15 M Vol. 0.090M KI H₂O2 10 ml 10 mL 20 mL 20 mL 10 mL 10 mL 9.1 x 104 mL M-2 sec-1 3.5 x 103 mL M-2 sec-1 5.3 x 104 mL M-2 sec-1 1.9 x 104 mL M-2 sec-1 Vol. H₂O 20 mL 30 mL 20 mL Rate (mL O₂/sec) 20 mL/sec 10 mL/sec 20 mL/sec
Using the data table and rate law given below, what is the value of the rate constant, k. Rate = K[H₂O₂][1]m Trial 1 Trial 2 Trial 3 Vol. 0.15 M Vol. 0.090M KI H₂O2 10 ml 10 mL 20 mL 20 mL 10 mL 10 mL 9.1 x 104 mL M-2 sec-1 3.5 x 103 mL M-2 sec-1 5.3 x 104 mL M-2 sec-1 1.9 x 104 mL M-2 sec-1 Vol. H₂O 20 mL 30 mL 20 mL Rate (mL O₂/sec) 20 mL/sec 10 mL/sec 20 mL/sec
Chapter30: Kinetic Methods Of Analysis
Section: Chapter Questions
Problem 30.7QAP
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![Using the data table and rate law given below, what is the value of the rate constant, k.
Rate = K[H₂O₂][1]
Trial
1
Trial
2
Trial
3
Vol. 0.15 M Vol. 0.090M
KI
H₂O2
10 ml
10 mL
20 mL
20 mL
10 mL
10 mL
9.1 x 104 mL M-2 sec-1
3.5 x 103 mL M-2 sec-1
5.3 x 104 mL M-2 sec-1
1.9 x 104 mL M-2 sec-1
Vol.
H₂O
20 mL
30 mL
20 mL
Rate (mL O₂/sec)
20 mL/sec
10 mL/sec
20 mL/sec](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9d604923-3a47-4675-abf7-07332cff4780%2F6875a513-bc4f-4d18-abba-f6f495b5d5a2%2F16fvc26_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Using the data table and rate law given below, what is the value of the rate constant, k.
Rate = K[H₂O₂][1]
Trial
1
Trial
2
Trial
3
Vol. 0.15 M Vol. 0.090M
KI
H₂O2
10 ml
10 mL
20 mL
20 mL
10 mL
10 mL
9.1 x 104 mL M-2 sec-1
3.5 x 103 mL M-2 sec-1
5.3 x 104 mL M-2 sec-1
1.9 x 104 mL M-2 sec-1
Vol.
H₂O
20 mL
30 mL
20 mL
Rate (mL O₂/sec)
20 mL/sec
10 mL/sec
20 mL/sec
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