Using the following reactions: (1) 2NH3g) + N2O»→ 4N2g) + 3H2O» AH = -1010 k) (2) 4NH3) + 302) → 2N2(@) + 6H2Ou) AH = -1531 k) AH for the reaction : N2) + ½ Ozie) → N¿Otg] i , k

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter5: Thermochemistry
Section: Chapter Questions
Problem 5.83QE: Calculate H when a 38-g sample of glucose, C6H12O6(s), burns in excess O2(g) to form CO2(g) and...
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Using the following reactions:
AH = -1010 k)
(1) 2NH3e + N2Og - 4N2e + 3H2O)
(2) 4NH3e + 30ze → 2N2g) + 6H2O
AH for the reaction : N2e) + ½ Oze) - N2Og is
AH = -1531 kJ
kJ.
Transcribed Image Text:Using the following reactions: AH = -1010 k) (1) 2NH3e + N2Og - 4N2e + 3H2O) (2) 4NH3e + 30ze → 2N2g) + 6H2O AH for the reaction : N2e) + ½ Oze) - N2Og is AH = -1531 kJ kJ.
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