Using the following snippet of code, introduce the walrus operator to re-write the code using less lines. inputs list() while True: current = input("Write something: ") Aim for half of the lines if current == "quit": break used while producing and preserving the same output that this code provides inputs.append (current)
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- What is the value of the following expressions (or ERROR)?1. __________ s.length()2. __________ t.length()3. __________ 1 + a4. __________ a.toUpperCase()5. __________ "Tomorrow".indexOf("r")6. __________ "Tomorrow".lastIndexOf('o')7. __________ "Tomorrow".substring(2,4)8. __________ (a.length() + a).startsWith("a")9. __________ s = = a10. __________ a.substring(1,3).equals("bc")Stack CreateStack(S) push (S, 10) push (S, 15) push (S, 20) x = top (S) push (S, x + 5) x = pop (S) + top (S) push (S, x – pop (S)) push (S, pop (pop (S))) push (S, x – top (S)) push (S, push(S, x) – top (S)) After executing the given codes above, answer the questions and explain. ThanksJAVA PROGRAM ASAP Modify thi program with further modifications which are down below: I have proded the test case that it needs to pass as a screen shot. The left index is inclusive and the right index is exclusive. 1. public static void bubbleSort(int[] array, int left, int right) { // your code here } 2. public static void insertionSort(int[] array, int left, int right) { // your code here } 3. public static void selectionSort(int[] array, int left, int right) { // your code here } import java.util.Arrays; import java.util.Scanner; public class Sort { public static void bubbleSort(int[] array) { int temp; for (int i = 0; i < array.length; ++i) { for (int j = 0; j < array.length - 1; ++j) { if (array[j] > array[j + 1]) { temp = array[j]; array[j] = array[j + 1]; array[j + 1] = temp; } } } }…
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- In this assignment you are required to implement the following using convolution . a) apply sharpen filter with different kernels, compare the results? You need to write program/ codeCorrect answer will be upvoted else downvoted. Computer science. Presently Nezzar has a beatmap of n particular focuses A1,A2,… ,An. Nezzar might want to reorder these n focuses so the subsequent beatmap is great. Officially, you are needed to find a change p1,p2,… ,pn of integers from 1 to n, to such an extent that beatmap Ap1,Ap2,… ,Apn is great. In case it is unthinkable, you ought to decide it. Input The primary line contains a solitary integer n (3≤n≤5000). Then, at that point, n lines follow, I-th of them contains two integers xi, yi (−109≤xi,yi≤109) — directions of point Ai. It is ensured that all focuses are unmistakable. Output In case there is no arrangement, print −1. In any case, print n integers, addressing a legitimate change p. In case there are numerous potential replies, you can print any.Can you help me fix my code because the total sum per item does not show in the receipt and when choosing to perform another transaction, the input for the customer's name and the number of items overlaps as seen in the image below. package cashier; import java.util.Scanner; class List { Scanner sc = new Scanner(System.in);private String name;private int item;private int[] des;private double price;private int[] quan;private double total;private double sum; public List(String name, int item, int[] des, double total, int[] quan, double sum) {this.name = name;this.item = item;this.des = des;this.quan = quan;this.total = total;this.sum = sum;}public void Input() {System.out.print("\n Enter name of customer: ");name = sc.nextLine();System.out.print(" Enter number of items: ");item = sc.nextInt();des = new int[item];quan = new int[item];total = 0; for (int i = 0; i < item; i++) {System.out.print("\n Enter item code: ");des[i] = sc.nextInt();for (int j = 0; j < item; j++) {if…
- Find all the indexes whose labels equal 2 using np.where and the label array y. The output should be saved in two class idx.Reminder: Remember to index np.where() at zero # TODO two_class_idx = np.where(y == 2 )[0] print(f"two_class_idx output: \n {two_class_idx}") try: print(f"two_class_idx shape: {two_class_idx.shape}") except Exception: pass ([ (isinstance(two_class_idx, np.ndarray),f'two_class_idx is not an NumPy array! two_class_idx is currently a {type(two_class_idx)}'), (np.all(two_class_idx == np.array([3,9,11,12,16])),'two_class_idx does not contain the correct location values') ])Write a program that benchmarks QuickSort and InsertionSort. You should use at least 5 different data sets and record the performance of each algorithm on the same sets under the same conditions. Write a short report that compares the two algorithms based your results. It is important to include a discussion of the initial states of the data sets in your report. language Java public class week3 {public static void main(String args[]){ //========================================================== //Question 1 testing //================== // Comment on benchmarking for Q1 results // // //========================================================== } static void quickSort(int f[], int p, int q){ if(q-p <= 1) ; //skip else{ int x; int i, j, k; // let x = middle element in f[p..q-1] x = f[(p+q)/2]; //x = f[p]; i = p; j = p; k = q; while(j != k){ if(f[j] == x) j = j + 1; else if(f[j] < x){ //swap f[j] with f[i] int temp; temp = f[j]; f[j] = f[i]; f[i] = temp; j = j + 1; i = i + 1; } else{…Urgent!!!!!! Need help in answering this question based on the information attached in the screenshot. The code should be in Java and should be able to pass all the test cases mentioned. We have to use a divide and conquer or a Greedy algorithm based on problem. Also the time complexity has to be as small as possible i.e the most optimal solution. If you use any references to get the code please link it as well. For reference this is the incomplete java code import java.io.*;import java.util.Arrays; public class Solution { public static void main(String[] args) throws Exception { BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); String[] parts = br.readLine().trim().split(" "); int n = Integer.parseInt(parts[0]); int k = Integer.parseInt(parts[1]); int f = Integer.parseInt(parts[2]); int h = Integer.parseInt(parts[3]); int[] hp_i = new int[n]; int[] d_j = new int[k]; for(int i = 0; i <…