Using the method of undetermined coefficients, find the particular solution of the following initial value problem: (a). y" + 4y' + 4y = 2te 4, 3(0) = 1, y (0) = –3 %3D %3D General Solutions: 3(t) = a ezp( exp(-2t) + exp( Applying initial conditions Particular Solutions: exp( t exp (b). y" - y – y = 0, 3(0) = 0, y'(0) = 3, y"(0) = 2 General Solutions: y(t) =Ci cos( D+ a sin( te ezp Applying initial conditions a Particular Solutions: y(t) + cos sin( ezp

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