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Using the provided table of Enthalpies of Formation, determine the enthalpy for the following reaction: 2C6H14(1) + 190,(g) → 12CO,(g) + 14H,O(g) AHf C6H14(1) = -199 kJ/mol AH¡ 02(g) = 0 kJ/mol AH¡ CO2(g) AHf H20(g) A. 8500 kJ/mol = -393 kJ/mol = -242 kJ/mol O B. -7700 kJ/mol OC. -8500 kJ/mol OD.7700 kJ/mol

Using the provided table of Enthalpies of Formation, determine the enthalpy for the following reaction: 2C6H14(1) + 190,(g) → 12CO,(g) + 14H,O(g) AHf C6H14(1) = -199 kJ/mol AH¡ 02(g) = 0 kJ/mol AH¡ CO2(g) AHf H20(g) A. 8500 kJ/mol = -393 kJ/mol = -242 kJ/mol O B. -7700 kJ/mol OC. -8500 kJ/mol OD.7700 kJ/mol

Chemistry
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter6: Thermochemistry
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Problem 76E: Combustion reactions involve reacting a substance with oxygen. When compounds containing carbon and...
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Using the provided table of Enthalpies of Formation, determine the enthalpy for the following reaction: 2C6H14(1) + 190:(g) - 12CO,(g) + 14H,O(g) AHf C6H14(1) = -199 kJ/mol AHf 02(a) = 0 kJ/mol AHf CO2(g) = -393 kJ/mol AHf H20(a) = -242 kJ/mol A. 8500 kJ/mol %3D B. -7700 kJ/mol OC. -8500 kJ/mol OD.7700 kJ/mol
Transcribed Image Text:Using the provided table of Enthalpies of Formation, determine the enthalpy for the following reaction: 2C6H14(1) + 190:(g) - 12CO,(g) + 14H,O(g) AHf C6H14(1) = -199 kJ/mol AHf 02(a) = 0 kJ/mol AHf CO2(g) = -393 kJ/mol AHf H20(a) = -242 kJ/mol A. 8500 kJ/mol %3D B. -7700 kJ/mol OC. -8500 kJ/mol OD.7700 kJ/mol
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