DEeres155./373839404142434445464748495051525354Rb SrY Zr Nb Mo TcRu Rh Pd Ag CdInSnSb TeI XeMytnn Technetium Ruthenium10107PalaumSarAtimony121.76StrumVtrmXonon131.29RubstumZeanumNobmRhodumCadmiumIndiamTinurmlodse87 291.2241029110 421077112411148211871127 5012630555657727374757677787980818283848586Cs Ba LaТаReOsAu Hg TI PbBi PoHfBarum Lanthanun Hanum17849WPtAt RnCesim13291Tantalum180Tungnen18384Osmum19023Gold19697Bisnuh208.98RhenumInidumPlatirumVercury200 5eThalum20438LaadPolonumAstatineRadan137 33139118621192 222072(201210(222)878889104105106107108109110111112114Fr Ra AcRf DbActinium tee Dubnium Senborgiun BohnumSg BhHs Mt Uun Uuu UubHassum MetneriumUuqFrandumRadum1287)201)120(2(2729)Br is oxidized and Na is reducedO A.I is oxidized and Br is reducedВ.OC.Na is oxidized and I is reducedI is oxidized and Na is reducedBr is oxidized and I is reduced Using the redox reaction given below, determine which element is oxidized and which element is reduced.2 Nal + Br2 → 2 NaBr + 12(The rules for assigning Oxidation States )1) The oxidation numbers of the atoms in a neutral molecule must add up to zero.2) Group I → +1 ; Group II → +2 ; Group III → +33) Fluorine → -1 (always)Halogens → -1 (except in compounds with O and other halogens)4) Hydrogen+1 (except in metal hydrides, e.g. LiH, Rule 2 and H has -1)5) Oxygen-2 (except in compounds with F, Rule 3)IAVIIIAHНеyngen1.00HelumIIAIIIAIVAVAVIAVIIA4.0006310LiВеB CNoF NeBurylumBorn10 11Caton12.011Onygen13Fuorne18LumNtrogen14.007Neon20 I01112131415161718MgMagnasiunSiCINaAISArPhosptorue30 974SodumSkoonSutrChorine36.453AuminumArgen220

In a reaction when the oxidation no of the atom increases from reactant to product then the atom is…

Answered: Using the redox reaction given below,…

Using the redox reaction given below, determine which element is oxidized and which element is reduced. 2 Nal + Br2 - 2 NaBr+ -12

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter3: Chemical Reactions

Section: Chapter Questions

Problem 113QRT

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Question

DE
eres
155./
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
Rb SrY Zr Nb Mo Tc
Ru Rh Pd Ag Cd
In
Sn
Sb Te
I Xe
Mytnn Technetium Ruthenium
10107
Palaum
Sar
Atimony
121.76
Strum
Vtrm
Xonon
131.29
Rubstum
Zeanum
Nobm
Rhodum
Cadmium
Indiam
Tin
urm
lodse
87 2
91.224
10291
10 42
1077
11241
11482
11871
127 50
12630
55
56
57
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
Cs Ba La
Та
Re
Os
Au Hg TI Pb
Bi Po
Hf
Barum Lanthanun Hanum
17849
W
Pt
At Rn
Cesim
13291
Tantalum
180
Tungnen
18384
Osmum
19023
Gold
19697
Bisnuh
208.98
Rhenum
Inidum
Platirum
Vercury
200 5e
Thalum
20438
Laad
Polonum
Astatine
Radan
137 33
1391
18621
192 22
2072
(20
1210
(222)
87
88
89
104
105
106
107
108
109
110
111
112
114
Fr Ra Ac
Rf Db
Actinium tee Dubnium Senborgiun Bohnum
Sg Bh
Hs Mt Uun Uuu Uub
Hassum Metnerium
Uuq
Frandum
Radum
1287)
201)
120
(2
(27
29)
Br is oxidized and Na is reduced
O A.
I is oxidized and Br is reduced
В.
OC.
Na is oxidized and I is reduced
I is oxidized and Na is reduced
Br is oxidized and I is reduced

Using the redox reaction given below, determine which element is oxidized and which element is reduced.
2 Nal + Br2 → 2 NaBr + 12
(The rules for assigning Oxidation States )
1) The oxidation numbers of the atoms in a neutral molecule must add up to zero.
2) Group I → +1 ; Group II → +2 ; Group III → +3
3) Fluorine → -1 (always)
Halogens → -1 (except in compounds with O and other halogens)
4) Hydrogen
+1 (except in metal hydrides, e.g. LiH, Rule 2 and H has -1)
5) Oxygen
-2 (except in compounds with F, Rule 3)
IA
VIIIA
H
Не
yngen
1.00
Helum
IIA
IIIA
IVA
VA
VIA
VIIA
4.0006
3
10
Li
Ве
B CNo
F Ne
Burylum
Born
10 11
Caton
12.011
Onygen
13
Fuorne
18
Lum
Ntrogen
14.007
Neon
20 I0
11
12
13
14
15
16
17
18
Mg
Magnasiun
Si
CI
Na
AI
S
Ar
Phosptorue
30 974
Sodum
Skoon
Sutr
Chorine
36.453
Auminum
Argen
220

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