Using the same information listed above for hair and eye color, (E = dominant brown eyes with e = recessive blue eyes; R = dominant brown hair and r = recessive blond hair), if the mom was heterozygous for both eye color and hair color what would her genotype be? a. EERRb. eerrc. EeRr What would be the 4 possible gametes the heterozygous mom could contribute? a. RE, Re, rE, reb. Rr, Ee, RE, rec. RR, rr, EE, ee OutsideeRFirstLastInsideListed below are the possible combinations of alleles the dad could contribute:eR, er, eR, erNote that some of the gametes are the same genotype, so the only unique gametes are: eR and er.Gamete Allele Combinations PracticeNow for some practice. Note that you are to list only ONE letter, representing an allele, on each of theblank lines below.Gamete Alleles 1Homework • UnansweredUsing the same information listed above for hair and eye color, (E = dominant brown eyes with e = recessive blue eyes; R=dominant brown hair and r= recessive blond hair), if the mom was heterozygous for both eye color and hair color what would hergenotype be?Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer.aEERRbeerr

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Description: Using the same information listed above for hair and eye color, (E = dominant brown eyes with e = recessive blue eyes; R = dominant brown hair and r = recessive blond hair), if the mom was heterozygous for both eye color and hair color what would her

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Using the same information listed above for hair and eye color, (E = dominant brown eyes with e = recessive blue eyes; R = dominant brown hair and r = recessive blond hair), if the mom was heterozygous for both eye color and hair color what would her genotype be? a. EERR b. eerr c. EeRr What would be the 4 possible gametes the heterozygous mom could contribute? a. RE, Re, rE, re b. Rr, Ee, RE, re c. RR, rr, EE, ee

Using the same information listed above for hair and eye color, (E = dominant brown eyes with e = recessive blue eyes; R = dominant brown hair and r = recessive blond hair), if the mom was heterozygous for both eye color and hair color what would her genotype be? a. EERR b. eerr c. EeRr What would be the 4 possible gametes the heterozygous mom could contribute? a. RE, Re, rE, re b. Rr, Ee, RE, re c. RR, rr, EE, ee

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter5: The Inheritance Of Complex Traits

Section: Chapter Questions

Problem 2QP: The text outlines some of the problems Frederick William I encountered in his attempt to breed tall...

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Mendelian GeneticsF1 Cross: Yellow, Round x Green, RoundGgWw x ggWWCharacter: Pea color & shapeUse Punnett square and fork-line method to check the F2.Show and interpret all the possible genotypes and phenotypes of the offsprings.Mendelian GeneticsF1 Cross: Tall, White, Axial x Dwarf, Violet, TerminalDdwwAA x ddWWaaCharacter: Stem height, Flower color & positionUse fork-line method to check the F2.Show and interpret all the possible genotypes and phenotypes of the offsprings.B.A.I. For A and B,1. Identify the type ofinheritance. Justifyyour answer.2. Decode the genotypesof the individuals inthe pedigree. (Useletter A forrepresentation ofalleles.)3. List down all affected
The letter that accompanies each trait is representative of the dominant allele. This is the letter you will use when recording the genotypic information for each trait. Read through the descriptions of the trait and determine which phenotype you express. Record your phenotype. Next, determine the genotype. If you express the dominant phenotype, you cannot determine the second allele you carry, so you must list the two possible genotypes. Record this down Question: Widow’s Peak (W): A hairline that forms a downward point in the middle of the forehead is caused by a dominant allele. A smooth hairline is caused by a recessive genotype.
Use Punnett Square:The letter that accompanies each trait is representative of the dominant allele. This is the letter you will use when recording the genotypic information for each trait.Read through the descriptions of each trait and determine which phenotype you express. Record your phenotypeNext, determine your genotype. If you express the dominant phenotype, you cannot determine the second allele you carry, so you must list the two possible genotypes. Record this. Question: Widow’s Peak (W): A hairline that forms a downward point in the middle of the forehead is caused by a dominant allele. A smooth hairline is caused by a recessive genotype.
In Figure 1-6, the students have 1 of 15 different heights,plus there are two height classes (4′11″ and 5′ 0″) forwhich there are no observed students. That is a total of17 height classes. If a single Mendelian gene can account for only two classes of a trait (such as purple orwhite flowers), how many Mendelian genes would beminimally required to explain the observation of 17height classes?
Write the number of different kinds of phenotypes,excluding sex, you would see among a large numberof progeny from an F1 mating between individuals ofidentical genotype that are heterozygous for one ortwo genes (that is, Aa or Aa Bb) as indicated. No geneinteractions means that the phenotype determined byone gene is not influenced by the genotype of theother gene.a. One gene; A completely dominant to a.b. One gene; A and a codominant.c. One gene; A incompletely dominant to a.d. Two unlinked genes; no gene interactions; Acompletely dominant to a, and B completelydominant to b.e. Two genes, 10 m.u. apart; no gene interactions; Acompletely dominant to a, and B completely dominant to b.f. Two unlinked genes; no gene interactions; A anda codominant, and B incompletely dominant to b.g. Two genes, 10 m.u. apart; A completely dominantto a, and B completely dominant to b; and withrecessive epistasis between aa and the alleles ofgene B.h. Two unlinked duplicated genes (that is, A and Bperform…
You are a genetic councilor and your first patients of the day have arrived. They have both tested positive as "carriers" of the rare cystic fibrosis allele f. Therefore each of them have the genotype Ff. They want to have a family but are worried that they might have a child who is affected with this disorder (ff). What is the probability that if they have a family of three children, two will be affected with cystic fibrosis, but exactly one of them will be unaffected. You must show your work to receive full credit.
The letter that accompanies each trait is representative of the dominant allele. This is the letter you will use when recording the genotypic information for each trait. Read through the descriptions of the trait and determine which phenotype you express. Record your phenotype. Next, determine the genotype. If you express the dominant phenotype, you cannot determine the second allele you carry, so you must list the two possible genotypes. Record this down Question: Ear lobes (E): Free ear lobes have at least one dominant allele. People with attached earlobes are recessive
Mendelian GeneticsF1 Cross: Yellow, Round x Green, Round GgWw x ggWWCharacter: Pea color & shapeUse Punnett square and fork-line method to check the F2.Show and interpret all the possible genotypes and phenotypes of the offsprings. Mendelian GeneticsF1 Cross: Tall, White, Axial x Dwarf, Violet, Terminal DdwwAA x ddWWaaCharacter: Stem height, Flower color & positionUse fork-line method to check the F2.Show and interpret all the possible genotypes and phenotypes of the offsprings. I. For A and B,1. Identify the type of inheritance. Justify your answer.2. Decode the genotypes of the individuals in the pedigree. (Use letter A for representation of alleles.)3. List down all affected individuals.B.A.
Two mothers give birth to sons at the same time at a busy urbanhospital. The son of mother 1 has hemophilia, a disease causedby an X-linked recessive allele. Neither parent has the disease.Mother 2 has a son without hemophilia, despite the fact thatthe father has hemophilia. Several years later, couple 1 suesthe hospital, claiming that these two newborns were swappedin the nursery following their birth. As a genetic counselor, youare called to testify. What information can you provide the juryconcerning the allegation?
Eye Color is a trait that involves a number of genes. To simplify our example, we can break down the traitinto two phenotypes: dark color and light color eyes. Dark coloration is considered dominant, or isexpressed in a heterozygous condition (when the alleles are different).Q: If you have one light eyed parent and one parent that is homozygous for dark eye color, what are thepotential eye colors of their offspring (young)? To start, what do the Parents’ alleles look like? What istheir Genotype? (Remember, you pick which letter you want to use)Light eye colored parent:Dark eye colored parent:One of the things Mendel designed was a way to provide information about how the genes are passed onfrom parent to offspring. He designed something called a Punnett Square. This square places the parents’alleles outside the box, then uses those alleles to fill in the squares.Let’s start with a reminder of what we know about the parents: Parent Phenotype(appearance) Genotype(alleles) 1 2
Complete the punnet square using the alleles you just listed. Comment: I can see that heterozygous is Rr and Homozygous is RR. But I still don’t understand how to do the punnet square.
For each of the following genotypes state whether you have a homozygous or heterozygous for each trait (you may need to use 2 terms for one genotype). AaGG Rrgg TTGg